Consider a database schema with the following relations: Student (ssn, name) Prof (ssn, name) Course (number, instructor-ssn, title, credits, room#) Enroll (student-ssn, course#) Room (number, capacity) Write an SQL query that finds the names of all students who are NOT enrolled in two classes held in the same room.
时间: 2024-03-30 16:35:29 浏览: 86
可以使用以下 SQL 查询语句来查找所有没有在同一教室上两门课程的学生姓名:
```
SELECT s.name
FROM Student s
WHERE s.ssn NOT IN (
SELECT e1.student-ssn
FROM Enroll e1, Enroll e2, Course c1, Course c2, Room r
WHERE e1.course# = c1.number
AND e2.course# = c2.number
AND c1.room# = c2.room#
AND c1.number != c2.number
AND c1.instructor-ssn = c2.instructor-ssn
AND e1.student-ssn = e2.student-ssn
AND r.number = c1.room#
AND e1.course# != e2.course#
)
```
这个查询使用了子查询来查找所有在同一教室上两门课程的学生,然后使用 NOT IN 子句来排除这些学生。最后,查询返回所有剩余的学生姓名。
相关问题
Consider a database schema with the following relations: Student (ssn, name) Prof (ssn, name) Course (number, instructor-ssn, title, credits, room#) Enroll (student-ssn, course#) Room (number, capacity) Write a relational algebra query that finds the names of all students who are enrolled in a class taught by “Jones”
可以使用以下关系代数查询语句来查找所有选修由“Jones”教授教授的课程的学生姓名:
```
σ Prof.name='Jones' (Course ⨝ Enroll ⨝ Student)
```
这个查询使用了自然连接和选择运算符。首先,我们使用自然连接将 Course 和 Enroll 关系连接,以获得所有选修课程的学生。然后,我们再将这个结果与 Student 关系连接,以获得学生姓名。最后,我们使用选择运算符来筛选出教授姓名为“Jones”的课程。
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