任意给4个数字（1-10），计算24点。写C++代码和Python代码

好的，以下是我提供的C++和Python代码，用于计算给定的4个数字的24点游戏结果：

C++代码：

#include <iostream>
using namespace std;

bool solve(double nums[], int n) {
    if (n == 1) {
        return fabs(nums[0] - 24) < 1e-6;
    }
    for (int i = 0; i < n; i++) {
        for (int j = i + 1; j < n; j++) {
            double a = nums[i], b = nums[j];
            nums[j] = nums[n - 1];
            for (int k = 0; k < 4; k++) {
                double c;
                if (k == 0) c = a + b;
                else if (k == 1) c = a - b;
                else if (k == 2) c = a * b;
                else {
                    if (fabs(b) < 1e-6) continue;
                    c = a / b;
                }
                nums[i] = c;
                if (solve(nums, n - 1)) return true;
            }
            nums[i] = a;
            nums[j] = b;
        }
    }
    return false;
}

int main() {
    double nums[4];
    for (int i = 0; i < 4; i++) {
        cin >> nums[i];
    }
    if (solve(nums, 4)) {
        cout << "YES" << endl;
    } else {
        cout << "NO" << endl;
    }
    return 0;
}

Python代码：

def solve(nums):
    if len(nums) == 1:
        return abs(nums[0] - 24) < 1e-6
    for i in range(len(nums)):
        for j in range(i + 1, len(nums)):
            a, b = nums[i], nums[j]
            nums[j] = nums[-1]
            for k in range(4):
                if k == 0:
                    c = a + b
                elif k == 1:
                    c = a - b
                elif k == 2:
                    c = a * b
                else:
                    if abs(b) < 1e-6:
                        continue
                    c = a / b
                nums[i] = c
                if solve(nums[:-1]):
                    return True
            nums[i], nums[j] = a, b
            nums[-1] = b
    return False

nums = list(map(int, input().split()))
if solve(nums):
    print("YES")
else:
    print("NO")