string dsf = endDateTime.ToString("yyyy-MM-dd HH:00:00"); DateTime startDateTime = DateTime.Parse(dsf);怎么简写成一步
时间: 2024-12-14 08:13:50 浏览: 8
你可以使用`DateTime.TryParseExact`方法来进行一步操作,这个方法可以直接尝试解析字符串并返回`DateTime`对象,如果解析成功则返回`true`。这样简化后的代码如下:
```csharp
DateTime? startDateTime = DateTime.TryParseExact(dsf, "yyyy-MM-dd HH:mm:ss", null, System.Globalization.DateTimeStyles.None, out DateTime parsedDateTime);
if (startDateTime.HasValue)
{
startDateTime = parsedDateTime;
}
else
{
// 如果解析失败,这里可以添加错误处理或默认值逻辑
}
```
在这个版本中,`TryParseExact`方法试图根据指定格式将字符串转换为`DateTime`。如果解析成功,结果被赋值给`parsedDateTime`,然后设置`startDateTime`。如果解析失败(`startDateTime.Value`为`null`),你需要额外处理这种情况。
相关问题
SimpleDateFormat dsf = new SimpleDateFormat("yyyy-MM"); String date = dsf.format(new Date()); Calendar calendar = Calendar.getInstance();
This code creates a SimpleDateFormat object with the format "yyyy-MM", which represents the year and month in a specific pattern. It then formats the current date using this format and stores it in a String variable called "date". Finally, it creates a Calendar object and sets it to the current date and time using the getInstance() method.
SimpleDateFormat dsf = new SimpleDateFormat("yyyy-MM");
This code creates a new instance of the SimpleDateFormat class with the format pattern "yyyy-MM", which represents the year and month in the format of "YYYY-MM", such as "2021-09". This pattern can be used to parse or format dates in this format.
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