double volumn = 1,0/3*PI*r*r*h;
时间: 2023-12-18 11:29:10 浏览: 24
根据提供的代码,double volumn = 1,0/3*PI*r*r*h; 这行代码是错误的。应该将1,0改为1.0,即1.0/3*PI*r*r*h。这行代码的作用是计算圆柱体的体积,而不是球体的体积。如果要计算球体的体积,应该使用4.0/3.0而不是1.0/3.0。下面是计算球体体积的代码示例:
```c
#include <stdio.h>
#define PI 3.14
int main() {
float radius, volume;
printf("请输入球的半径:");
scanf("%f", &radius);
if (radius >= 0) {
volume = 4.0 / 3.0 * PI * radius * radius * radius;
printf("半径为%.2f的球的体积是%.2f\n", radius, volume);
}
return 0;
}
```
相关问题
import collections import math coordinate_X = [3, 8, 2, 6, 8] coordinate_Y = [8, 2, 5, 4, 8] Rate = [5, 5, 7.5, 7.5, 7.5] Volumn = [20, 30, 25, 10, 15] length = len(coordinate_X) temp_x = [] temp_y = [] temp_z = [] # 第一次坐标值计算 for i in range(length): temp_x.append(Rate[i] * Volumn[i] * coordinate_X[i]) temp_y.append(Rate[i] * Volumn[i] * coordinate_Y[i]) temp_z.append(Rate[i] * Volumn[i]) sigma_x = 0 sigma_y = 0 sigma_z = 0 for i in range(length): sigma_x += temp_x[i] sigma_y += temp_y[i] sigma_z += temp_z[i] before_x = sigma_x / sigma_z before_y = sigma_y / sigma_z print("第一次的坐标值", before_x, before_y) # 继续优化坐标值 flag = 1 while flag != 0: before_dis = [] for i in range(length): before_dis.append( math.sqrt((before_x - coordinate_X[i]) ** 2 + (before_y - coordinate_Y[i]) ** 2)) temp_xm = [] temp_ym = [] temp_zm = [] for i in range(length): temp_xm.append(Rate[i] * Volumn[i] * coordinate_X[i] / before_dis[i]) temp_ym.append(Rate[i] * Volumn[i] * coordinate_Y[i] / before_dis[i]) temp_zm.append(Rate[i] * Volumn[i] / before_dis[i]) sigma_xm = 0 sigma_ym = 0 sigma_zm = 0 for i in range(length): sigma_xm += temp_xm[i] sigma_ym += temp_ym[i] sigma_zm += temp_zm[i] after_x = sigma_xm / sigma_zm after_y = sigma_ym / sigma_zm after_dis = [] for i in range(length): after_dis.append(math.sqrt((after_x - coordinate_X[i]) ** 2 + (after_y - coordinate_Y[i]) ** 2)) before_TC = 0 after_TC = 0 for i in range(length): before_TC += (Rate[i] * Volumn[i] * before_dis[i]) after_TC += (Rate[i] * Volumn[i] * after_dis[i]) if before_TC > after_TC and before_TC-after_TC<0.002: print("第", flag, "次坐标值是", after_x, after_y) flag += 1 before_x = after_x before_y = after_y else: flag = 0这个代码如何在迭代结果=0.002时停止并输出
可以在代码中加入一个判断条件,在 before_TC 和 after_TC 差值小于等于 0.002 时停止迭代并输出最终结果。以下是修改后的代码:
```python
import collections
import math
coordinate_X = [3, 8, 2, 6, 8]
coordinate_Y = [8, 2, 5, 4, 8]
Rate = [5, 5, 7.5, 7.5, 7.5]
Volumn = [20, 30, 25, 10, 15]
length = len(coordinate_X)
temp_x = []
temp_y = []
temp_z = []
# 第一次坐标值计算
for i in range(length):
temp_x.append(Rate[i] * Volumn[i] * coordinate_X[i])
temp_y.append(Rate[i] * Volumn[i] * coordinate_Y[i])
temp_z.append(Rate[i] * Volumn[i])
sigma_x = 0
sigma_y = 0
sigma_z = 0
for i in range(length):
sigma_x += temp_x[i]
sigma_y += temp_y[i]
sigma_z += temp_z[i]
before_x = sigma_x / sigma_z
before_y = sigma_y / sigma_z
print("第一次的坐标值", before_x, before_y)
# 继续优化坐标值
flag = 1
while flag != 0:
before_dis = []
for i in range(length):
before_dis.append(
math.sqrt((before_x - coordinate_X[i]) ** 2 + (before_y - coordinate_Y[i]) ** 2))
temp_xm = []
temp_ym = []
temp_zm = []
for i in range(length):
temp_xm.append(Rate[i] * Volumn[i] * coordinate_X[i] / before_dis[i])
temp_ym.append(Rate[i] * Volumn[i] * coordinate_Y[i] / before_dis[i])
temp_zm.append(Rate[i] * Volumn[i] / before_dis[i])
sigma_xm = 0
sigma_ym = 0
sigma_zm = 0
for i in range(length):
sigma_xm += temp_xm[i]
sigma_ym += temp_ym[i]
sigma_zm += temp_zm[i]
after_x = sigma_xm / sigma_zm
after_y = sigma_ym / sigma_zm
after_dis = []
for i in range(length):
after_dis.append(math.sqrt((after_x - coordinate_X[i]) ** 2 + (after_y - coordinate_Y[i]) ** 2))
before_TC = 0
after_TC = 0
for i in range(length):
before_TC += (Rate[i] * Volumn[i] * before_dis[i])
after_TC += (Rate[i] * Volumn[i] * after_dis[i])
if before_TC - after_TC <= 0.002:
print("第", flag, "次坐标值是", after_x, after_y)
flag = 0
else:
print("第", flag, "次坐标值是", after_x, after_y)
flag += 1
before_x = after_x
before_y = after_y
```
在修改后的代码中,增加了一个判断条件 `if before_TC - after_TC <= 0.002:`,当 before_TC 和 after_TC 差值小于等于 0.002 时,停止迭代并输出最终结果。同时,在迭代过程中,增加了输出每次迭代结果的代码,方便查看。
预测分析表构建,rule = [list('S->aA'), list('S->d'), list('A->bAS'), list('A->*')] vn = ['S', 'A'] vt = ['a', 'b', 'd'] start = 'S'# 该文法是LL(1)文法\n def printchat(): M = PrettyTable() # 表格形式的预测分析表 M.title='预测分析表' temp_vt = copy.deepcopy(vt) temp_vt.append('#') # 在终结符中加入# volumn = [''] # 定义表格形式预测分析表的列名 volumn.extend(temp_vt) M.field_names = volumn for k in vn: lis=[k] for alphabet in temp_vt: flag=0 for r in range(len(rule)): # if alphabet in s[r] and rule[r][0]==vn[k]: if alphabet in s[r] and k == rule[r][0]: flag=1 str1 = ''.join(rule[r]) lis.append(str1) break if flag == 0: lis.append(' ') M.add_row(lis) print(M),给出过程
首先,我们需要计算出该文法的FIRST集和FOLLOW集。假设该文法的FIRST和FOLLOW集如下:
FIRST集:
FIRST(S) = {a, d}
FIRST(A) = {b, *}
FOLLOW集:
FOLLOW(S) = {$}
FOLLOW(A) = {a, $}
接下来,我们需要构建预测分析表。预测分析表的行表示非终结符,列表示终结符。
首先,我们需要将终结符集合中的符号添加上结束符号#。因此,我们得到了新的终结符集合:{'a', 'b', 'd', '#'}
接下来,我们需要初始化一个表格形式的预测分析表,以及列名。我们的列名包含了终结符集合。
然后,我们需要遍历每一个非终结符,对于每一个终结符,我们需要查找该非终结符生成的每一个产生式中是否包含该终结符。如果包含,我们就需要将该产生式填入预测分析表中对应的位置。
具体的过程如下:
1. 初始化表格形式的预测分析表和列名
```
M = PrettyTable() # 表格形式的预测分析表
M.title = '预测分析表'
temp_vt = copy.deepcopy(vt)
temp_vt.append('#') # 在终结符中加入#
volumn = ['']
volumn.extend(temp_vt)
M.field_names = volumn
```
2. 对于每一个非终结符,查找它生成的每一个产生式,判断是否包含终结符
```
for k in vn:
lis = [k]
# 对于每一个终结符,查找是否在该非终结符生成的产生式中
for alphabet in temp_vt:
flag = 0 # 标记是否查找到了该终结符
for r in range(len(rule)):
# 判断该终结符是否在该产生式右部出现
if alphabet in rule[r][1:] and k == rule[r][0]:
flag = 1
str1 = ''.join(rule[r])
lis.append(str1)
break
if flag == 0:
lis.append(' ')
M.add_row(lis)
```
最后,输出预测分析表。
```
print(M)
```