TypeError: __init__() got multiple values for argument 'params'
时间: 2023-08-02 07:07:09 浏览: 681
这个错误是由于在创建对象时给参数 'params' 传递了多个值导致的。在 Python 中,每个参数只应该有一个值。
例如,如果你有一个类定义如下:
```python
class MyClass:
def __init__(self, params):
self.params = params
```
然后创建对象时,只能传递一个值给 'params' 参数,像这样:
```python
my_object = MyClass(my_params)
```
如果你传递了多个值,就会出现上述的 TypeError。请检查你创建对象时的代码,确保只传递了一个值给 'params' 参数。如果问题仍然存在,请提供更多的代码和错误上下文,以便我能够更好地帮助你解决问题。
相关问题
TypeError: __init__() got multiple values for argument 'filters'
This error occurs when the `__init__()` method of a class is called with multiple values for the same argument.
For example, if you have a class `MyClass` with an `__init__()` method that takes a `filters` argument:
```
class MyClass:
def __init__(self, filters):
self.filters = filters
```
And you create an instance of this class and pass multiple values for `filters`:
```
my_instance = MyClass(filters='value1', filters='value2')
```
You will get the `TypeError: __init__() got multiple values for argument 'filters'` error.
To fix this error, make sure that you are only passing one value for each argument in the `__init__()` method. In the above example, you could pass a list of values for `filters` instead:
```
my_instance = MyClass(filters=['value1', 'value2'])
```
TypeError: __init__() got multiple values for argument 'strides'
This error occurs when you pass multiple values for the same argument in the initialization of an object or function.
For example, if you have a class that takes in a 'strides' argument in its __init__() method and you pass multiple values for 'strides' like this:
```
class MyClass:
def __init__(self, strides):
self.strides = strides
my_object = MyClass(strides=2, strides=3)
```
You will get the TypeError: __init__() got multiple values for argument 'strides'
To fix this error, make sure you are passing only one value for each argument. In the example above, you can fix the error by passing only one value for 'strides':
```
my_object = MyClass(strides=2)
```