C语言-----石头剪刀布小游戏控制胜率

以下是一个C语言实现的石头剪刀布小游戏，可以控制胜率的示例代码：

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main() {
    int play, computer, winCount = 0, loseCount = 0, drawCount = 0;
    char choice;

    srand(time(NULL));

    do {
        printf("请选择：\n");
        printf("1. 石头\n");
        printf("2. 剪刀\n");
        printf("3. 布\n");
        printf("0. 退出\n");
        scanf("%d", &play);

        if (play == 0) {
            break;
        }

        computer = rand() % 3 + 1;

        printf("你选择了：");
        switch (play) {
            case 1:
                printf("石头\n");
                break;
            case 2:
                printf("剪刀\n");
                break;
            case 3:
                printf("布\n");
                break;
            default:
                printf("无效选择\n");
                continue;
        }

        printf("电脑选择了：");
        switch (computer) {
            case 1:
                printf("石头\n");
                break;
            case 2:
                printf("剪刀\n");
                break;
            case 3:
                printf("布\n");
                break;
        }

        if (play == computer) {
            printf("平局！\n");
            drawCount++;
        } else if ((play == 1 && computer == 2) || (play == 2 && computer == 3) || (play == 3 && computer == 1)) {
            printf("你赢了！\n");
            winCount++;
        } else {
            printf("你输了！\n");
            loseCount++;
        }

        printf("胜利次数：%d，失败次数：%d，平局次数：%d\n", winCount, loseCount, drawCount);

        printf("是否继续游戏？(y/n) ");
        scanf(" %c", &choice);
    } while (choice == 'y' || choice == 'Y');

    return 0;
}

这个程序使用了随机数生成电脑的选择，然后根据玩家和电脑的选择进行比较，判断胜负或平局，并统计胜利、失败和平局的次数。你可以通过多次运行程序来控制胜率。