DEC_PRJ_CUT_HEAD a LEFT JOIN COPSEAL U ON ISNULL(U.COPID,'')=ISNULL(A.FID,'') AND ISNULL(U.ISSTOPPED,'')<>'1' AND ISNULL(U.ISDEFAULT,'')='1,解释一下这一段sql
时间: 2023-08-20 14:57:51 浏览: 44
这段SQL是一个左连接查询,从表`DEC_PRJ_CUT_HEAD`和表`COPSEAL`中获取数据。它使用`LEFT JOIN`关键字指定以`DEC_PRJ_CUT_HEAD`表为主表,将匹配的记录从`COPSEAL`表中取出。
连接条件是通过比较两个表中的`FID`和`COPID`字段。这里使用了`ISNULL`函数来处理可能的空值情况,即将空值转换为空字符串进行比较。
另外,在连接条件中加入了一些额外的筛选条件,通过使用`ISNULL`函数和逻辑运算符来过滤符合特定条件的记录。具体条件是:
- `U.ISSTOPPED<>'1'`:排除`COPSEAL`表中`ISSTOPPED`字段值为1的记录。
- `U.ISDEFAULT='1'`:筛选出`COPSEAL`表中`ISDEFAULT`字段值为1的记录。
以上就是这段SQL语句的解释。如果还有其他问题,请继续提问。
相关问题
SELECT Prj_DBName FROM kiyunstm_bq.t_projects 查询出库名,然后根据库名查询SELECT s.Prj_Uid,v.Version_No,CONCAT( s.Soft_Name , '-',vtl.VTL_TechStrategy ) AS Test_level_name,a.TestItem,a.testType,a.use_cases,b.instance_data, CONCAT( a.use_cases , '/',b.instance_data) AS cases_instances FROM t_softlist AS s INNER JOIN t_testversion AS v ON v.TreeUid = s.TreeUid INNER JOIN t_versiontotestlevel AS vtl ON vtl.Version_Uid = v.Version_Uid LEFT JOIN view_soft_testreqcanbuildusecase AS qcan ON qcan.VTL_Uid = vtl.VTL_Uid LEFT JOIN ( SELECT qcan.TestItem,qcan.testType,COUNT(us.TreeUid) AS use_cases FROM view_soft_testreqcanbuildusecase AS qcan INNER JOIN t_usecase AS us ON us.TreeUid = qcan.ReqTreeUid GROUP BY qcan.TestType )AS a ON a.TestItem = qcan.TestItem LEFT JOIN ( SELECT qcan.TestItem,qcan.testType,COUNT(uci.UC_Uid) AS instance_data FROM view_soft_testreqcanbuildusecase AS qcan INNER JOIN t_usecase AS us ON us.TreeUid = qcan.ReqTreeUid INNER JOIN t_ucinstances AS uci ON uci.UC_Uid = us.UC_Uid GROUP BY qcan.TestType )AS b ON b.testType = a.testType GROUP BY Test_level_name,a.TestType
要根据前一个查询结果中的库名查询相关信息,你可以将第一个查询作为子查询,并在第二个查询中使用这个子查询的结果。以下是修改后的查询语句示例:
```
SELECT s.Prj_Uid, v.Version_No, CONCAT(s.Soft_Name, '-', vtl.VTL_TechStrategy) AS Test_level_name, a.TestItem, a.testType, a.use_cases, b.instance_data,
CONCAT(a.use_cases, '/', b.instance_data) AS cases_instances
FROM t_softlist AS s
INNER JOIN t_testversion AS v ON v.TreeUid = s.TreeUid
INNER JOIN t_versiontotestlevel AS vtl ON vtl.Version_Uid = v.Version_Uid
LEFT JOIN view_soft_testreqcanbuildusecase AS qcan ON qcan.VTL_Uid = vtl.VTL_Uid
LEFT JOIN (
SELECT qcan.TestItem, qcan.testType, COUNT(us.TreeUid) AS use_cases FROM view_soft_testreqcanbuildusecase AS qcan
INNER JOIN t_usecase AS us ON us.TreeUid = qcan.ReqTreeUid
GROUP BY qcan.TestType
) AS a ON a.TestItem = qcan.TestItem
LEFT JOIN (
SELECT qcan.TestItem, qcan.testType, COUNT(uci.UC_Uid) AS instance_data FROM view_soft_testreqcanbuildusecase AS qcan
INNER JOIN t_usecase AS us ON us.TreeUid = qcan.ReqTreeUid
INNER JOIN t_ucinstances AS uci ON uci.UC_Uid = us.UC_Uid
GROUP BY qcan.TestType
) AS b ON b.testType = a.testType
WHERE s.Prj_Uid IN (
SELECT Prj_Uid
FROM kiyunstm_bq.t_projects
)
GROUP BY s.Prj_Uid, Test_level_name, a.TestType;
```
在这个查询语句中,我们添加了一个`WHERE`子句,使用`IN`关键字将第一个查询结果中的库名作为条件进行筛选。请确保将`t_projects`和其他表名替换为实际的表名。
SELECT b.ID, b.audit_code, b.project_id, b.flow_end_date businessClosedDate, P.outterbalance_money, P.project_code, P.project_name, 'ZC' closeTypeCode, b.flow_status FROM pms_pm_project_business_close b LEFT JOIN pms_pm_prj_base P ON P.ID = b.project_id LEFT JOIN pms_CONTRACT_PORJECT_RELATION C ON P.ID = C.eps_id AND C.status = 0 WHERE b.status = 0 AND P.status = 0 AND C.contract_id ='CA0B8794AD700001B77A87201855D970' UNION SELECT b.ID, b.audit_code, b.project_id, b.business_close_date businessClosedDate, P.outterbalance_money, P.project_code, P.project_name, 'YC' closeTypeCode, CASE WHEN b.flow_status = 2 THEN '流程结束' WHEN b.flow_status = 1 THEN '审批中' ELSE'拟稿' END flow_status FROM pms_pm_project_unusual_close b LEFT JOIN pms_pm_prj_base P ON P.ID = b.project_id LEFT JOIN pms_CONTRACT_PORJECT_RELATION C ON P.ID = C.eps_id AND C.status = 0 WHERE b.status = 0 AND b.IS_BUSINESS_CLOSE_CODE = '1' AND P.status = 0 AND C.contract_id ='CA0B8794AD700001B77A87201855D970' 解决这段sql的问题 UNION types numeric and text cannot be matched
这个错误通常是由于两个 SELECT 语句的列数据类型不匹配导致的。在 UNION 操作中,两个 SELECT 语句的列列表必须具有相同的数据类型或可以进行隐式转换。
根据您提供的 SQL 查询语句,我注意到在第一个 SELECT 子句中,'ZC' 被用作 closeTypeCode 的值。而在第二个 SELECT 子句中,使用了一个 CASE 表达式来确定 flow_status 的值。
请确保 closeTypeCode 和 flow_status 的数据类型相匹配,以便在 UNION 操作中正确匹配列。如果 closeTypeCode 的数据类型为文本类型(varchar、text),您可以将 flow_status 的值转换为文本类型,例如将数字 2 转换为字符串 '2'。
例如,您可以尝试修改第二个 SELECT 子句的 CASE 表达式如下:
```sql
CASE
WHEN b.flow_status = 2 THEN '流程结束'
WHEN b.flow_status = 1 THEN '审批中'
ELSE '拟稿'
END AS flow_status
```
通过添加 `AS flow_status`,确保 flow_status 是一个别名,并且与第一个 SELECT 子句中的列名相匹配。
请尝试修改查询并检查列数据类型是否匹配,这样就可以解决 UNION types numeric and text cannot be matched 的问题。如果您有其他问题,请随时提问!