ros2 moveit2 python求速度雅可比矩阵示例
时间: 2024-08-16 12:05:41 浏览: 170
在ROS2 MoveIt2库中,速度雅可比矩阵是一个关键的概念,它用于规划机器人关节的速度路径。在Python中,你可以通过`moveit_msgs`包下的`RobotState`消息以及`PlanningScene`和`MoveGroupInterface`等工具来获取和操作这个矩阵。
以下是一个简单的示例,展示了如何计算并打印速度雅可比矩阵:
```python
import rclpy
from rclpy.node import Node
from geometry_msgs.msg import PoseStamped
from moveit_msgs.msg import RobotState
from std_msgs.msg import Float64MultiArray
class MoveItExample(Node):
def __init__(self):
super().__init__('moveit_example')
self.move_group = self.create_client('compute_cartesian_path', 'move_group')
self.get_logger().info('Waiting for compute_cartesian_path service...')
while not self.move_group.wait_for_service(timeout_sec=5.0):
self.get_logger().info('compute_cartesian_path service not available, waiting again...')
self.pose_stamped = PoseStamped()
# ... 设置初始或目标位置 ...
def get_speed_jacobian(self):
# 假设已经得到了RobotState msg
robot_state_msg = self.get_robot_state()
# 提取JointModelGroup信息
group_name = robot_state_msg.joint_state.name # 假定只有一个运动组
group_info = self.declare_rosparam("robot_description").get_child(group_name).to_yaml_dict()['kinematic_model']['joint_model_group']
# 计算速度雅可比矩阵
jacobians = robot_state_msg.joint_state.velocity
speed_jac = []
for joint, jac in zip(group_info['joints'], jacobians):
speed_jac.append([jac])
return Float64MultiArray(data=speed_jac)
def get_robot_state(self):
# 获取当前机器人状态
future = self.move_group.call_async(lambda req: req)
self.create_subscription(RobotState, '/robot_state', self.robot_state_callback, 1)
while rclpy.ok():
rclpy.spin_once(self)
if future.done():
result = future.result()
break
return result.state
def robot_state_callback(self, data):
# 存储接收到的RobotState数据
self.robot_state = data
def execute(self):
try:
# 调用服务函数获取路径
resp = self.move_group.call(self.create_request())
# 如果成功,打印速度雅可比矩阵
if resp.error_code.val == ExecuteResult.SUCCESS:
jacobian_array = self.get_speed_jacobian()
self.get_logger().info(f"Speed Jacobian: {jacobian_array.data}")
except Exception as e:
self.get_logger().error(f"Failed to compute path: {e}")
def main(args=None):
rclpy.init(args=args)
node = MoveItExample()
node.execute()
rclpy.shutdown()
if __name__ == '__main__':
main()
```
在这个示例中,我们首先创建了一个Node并等待`compute_cartesian_path`服务可用。然后在`execute`方法里,我们计算了速度雅可比矩阵,并在得到路径成功的情况下将其打印出来。请注意,这只是一个基础示例,实际应用中可能需要处理更多细节,如错误处理和服务调用阻塞。
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