def size1(n): for i in range(n): print("".rjust(2*i+1,"*")) 这种怎么用return
时间: 2024-05-26 12:12:33 浏览: 108
这个函数可以使用return来返回一个字符串,而不是直接打印出来。例如:
def size1(n):
result = ""
for i in range(n):
result += "".rjust(2*i + 1, "*") + "\n"
return result
print(size1(5))
输出:
*
***
*****
*******
*********
相关问题
def size1(n): result = "" for i in range(n): result = "".rjust(2 * i + 1, "*") + "\n" return result
The function size1(n) appears to be incomplete and contains errors. Here is a revised version of the function that will return a string of asterisks (*) arranged in a pyramid shape:
```
def size1(n):
result = ""
for i in range(1, n + 1):
row = "* " * i
result += row.center(n * 2 - 1) + "\n"
return result
```
Explanation:
1. `result = ""` initializes an empty string that will be used to store the pyramid.
2. `for i in range(1, n + 1):` loops through the numbers 1 to n (inclusive).
3. `row = "* " * i` creates a string of asterisks and spaces, with i asterisks and i - 1 spaces.
4. `result += row.center(n * 2 - 1) + "\n"` centers the row string in a field of width n * 2 - 1 (to account for the spaces between asterisks), adds a newline character at the end, and appends it to the result string.
5. `return result` returns the completed pyramid string.
Example usage:
```
>>> print(size1(5))
*
* *
* * *
* * * *
* * * * *
```
Note that the pyramid is centered and has a base width of n * 2 - 1.
一个数如果恰好等于它的所有因子(不包括它自己)之和,就称其为完数,比如6=1+2+3。输出n之内的全部“完数”,n从键盘上输入。这里保证输入的n值是正整数,读者无需考虑。 输出中,每个数占的宽度为6,右对齐
完数是指一个数恰好等于其除自身以外的所有因数之和。我们可以编写一个程序来找出指定范围内(n以内)的所有完数。首先,我们需要遍历从2到n,对于每一个数,计算其因数之和,如果这个和正好等于该数本身,则将其添加到结果列表中。
下面是一个简单的Python代码示例,用于找到并输出n范围内的完数:
```python
def find_perfect_numbers(n):
perfect_numbers = []
for num in range(2, n + 1):
factors_sum = sum(i for i in range(1, num) if num % i == 0)
if factors_sum == num:
perfect_numbers.append(str(num).rjust(6)) # 右对齐,宽度为6
return perfect_numbers
# 用户输入n值
n = int(input("请输入n的值:"))
perfects_in_range = find_perfect_numbers(n)
print("在{}内的完数有:".format(n))
for perfect in perfects_in_range:
print(perfect)
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