给我写一个批量从gitlab下载代码的脚本，当分组下有子分组时则根据子分组创建文件夹并下载代码

以下是一个简单的Python脚本，可以批量从GitLab下载代码，并按照子分组创建文件夹。

import os
import gitlab

# GitLab服务器的URL和访问令牌
GITLAB_URL = "https://gitlab.example.com"
GITLAB_TOKEN = "your_access_token"

# 要下载的项目所在的分组ID
GROUP_ID = 123

# 本地保存代码的根目录
LOCAL_DIR = "/path/to/local/dir"

# 连接到GitLab服务器
gl = gitlab.Gitlab(GITLAB_URL, private_token=GITLAB_TOKEN)

# 获取指定分组下的所有子分组
def get_subgroups(group_id):
    subgroups = []
    group = gl.groups.get(group_id)
    for subgroup in group.subgroups.list(all=True):
        subgroups.append(subgroup)
        subgroups.extend(get_subgroups(subgroup.id))
    return subgroups

# 在本地创建目录，如果已经存在则不创建
def create_dir(path):
    if os.path.exists(path):
        return
    os.makedirs(path)

# 下载指定项目到本地
def download_project(project, local_path):
    create_dir(local_path)
    repo = gl.projects.get(project.id).repository_archive()
    with open(local_path + "/archive.zip", "wb") as f:
        f.write(repo)

# 下载指定分组下的所有项目
def download_projects_in_group(group):
    projects = group.projects.list(all=True)
    for project in projects:
        local_path = LOCAL_DIR + "/" + group.name + "/" + project.name
        download_project(project, local_path)

# 下载指定分组及其子分组下的所有项目
def download_projects_in_group_and_subgroups(group):
    download_projects_in_group(group)
    subgroups = get_subgroups(group.id)
    for subgroup in subgroups:
        local_path = LOCAL_DIR + "/" + group.name + "/" + subgroup.name
        download_projects_in_group(subgroup, local_path)

# 开始下载
group = gl.groups.get(GROUP_ID)
download_projects_in_group_and_subgroups(group)

在运行脚本之前，需要安装 `python-gitlab` 模块：

pip install python-gitlab

另外，需要将 `GITLAB_URL`、`GITLAB_TOKEN`、`GROUP_ID` 和 `LOCAL_DIR` 替换为实际的值。