#!/bin/bash users=$(cut -d: -f1 /etc/passwd) for user in $users do if [[ $(getent passwd $user | cut -d: -f3) -ge 1000 ]] then if [[ $(chage -l $user | grep "Password expires" | grep "密码过期时间" | cut -d: -f2 | tr -d ' ') == "never" || $(chage -l $user | grep "Password expires" | grep "密码过期时间" | cut -d: -f2 | tr -d ' ') == "从不" ]] then echo "$user: Password never expires" else expire_date=$(date -d "$(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')" +%s) current_date=$(date +%s) if [[ $expire_date -lt $current_date ]] then echo "$(hostname -I | awk '{print $1}'), $user: Password has expired" else echo "$user: Password will expire on $(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')" fi fi else account_status=$(passwd -S $user | awk '{print $2}') if [[ "$account_status" == "L" ]]; then echo "$(hostname -I | awk '{print $1}'), User $user: account locked!" fi fi done帮我把这段代码的第一个if去掉

好的，这是去掉第一个if之后的代码：

#!/bin/bash 
users=$(cut -d: -f1 /etc/passwd) 
for user in $users 
do 
    if [[ $(chage -l $user | grep "Password expires" | grep "密码过期时间" | cut -d: -f2 | tr -d ' ') == "never" || $(chage -l $user | grep "Password expires" | grep "密码过期时间" | cut -d: -f2 | tr -d ' ') == "从不" ]] 
    then 
        echo "$user: Password never expires" 
    else 
        expire_date=$(date -d "$(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')" +%s) 
        current_date=$(date +%s) 
        if [[ $expire_date -lt $current_date ]] 
        then 
            echo "$(hostname -I | awk '{print $1}'), $user: Password has expired" 
        else 
            echo "$user: Password will expire on $(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')" 
        fi 
    fi 
    account_status=$(passwd -S $user | awk '{print $2}') 
    if [[ "$account_status" == "L" ]]; then 
        echo "$(hostname -I | awk '{print $1}'), User $user: account locked!" 
    fi 
done

注意，去掉了第一个if语句后，需要将原代码中的第二个if移动到第一个if的位置，以保证逻辑正确。