使用java代码实现找出多个时间段,中间缺失的时间段
时间: 2023-06-04 11:07:32 浏览: 104
好的,我可以帮助你解答这个问题。你可以通过以下代码实现找出多个时间段,中间缺失的时间段:
```java
import java.time.Duration;
import java.time.LocalDateTime;
import java.util.ArrayList;
import java.util.List;
public class MissingTimeInterval {
public static void main(String[] args) {
List<TimeInterval> intervals = new ArrayList<>();
intervals.add(new TimeInterval(LocalDateTime.parse("2022-01-01T00:00:00"),
LocalDateTime.parse("2022-01-01T02:00:00")));
intervals.add(new TimeInterval(LocalDateTime.parse("2022-01-01T05:00:00"),
LocalDateTime.parse("2022-01-01T06:00:00")));
intervals.add(new TimeInterval(LocalDateTime.parse("2022-01-01T08:00:00"),
LocalDateTime.parse("2022-01-01T10:00:00")));
List<TimeInterval> missingIntervals = findMissingIntervals(intervals);
for (TimeInterval missingInterval : missingIntervals) {
System.out.println("Missing interval: " + missingInterval.getStart() + " - " + missingInterval.getEnd());
}
}
public static List<TimeInterval> findMissingIntervals(List<TimeInterval> intervals) {
List<TimeInterval> missingIntervals = new ArrayList<>();
if (intervals.size() == 0) {
return missingIntervals;
}
LocalDateTime startTime = intervals.get(0).getStart();
for (int i = 1; i < intervals.size(); i++) {
LocalDateTime endTime = intervals.get(i).getStart();
if (!startTime.plus(Duration.ofHours(1)).equals(endTime)) {
missingIntervals.add(new TimeInterval(startTime.plus(Duration.ofMinutes(1)), endTime.minus(Duration.ofMinutes(1))));
}
startTime = intervals.get(i).getEnd();
}
return missingIntervals;
}
}
class TimeInterval {
private LocalDateTime start;
private LocalDateTime end;
public TimeInterval(LocalDateTime start, LocalDateTime end) {
this.start = start;
this.end = end;
}
public LocalDateTime getStart() {
return start;
}
public LocalDateTime getEnd() {
return end;
}
}
```
这段代码定义了一个 TimeInterval 类,用于表示时间段。findMissingIntervals() 方法可以接收多个时间段,并返回其中中间缺失的时间段。在 main() 方法中,我们定义了三个时间段,并使用 findMissingIntervals() 方法查找中间缺失的时间段,并将结果输出到控制台上。
阅读全文