template with Clinkage
时间: 2023-07-18 15:36:11 浏览: 38
在C++中,当使用模板时,模板函数的名称会被C++编译器进行名称修饰。这导致在C++代码中使用模板函数时,无法直接与C语言进行互操作。为了解决这个问题,可以使用"extern C++"关键字来告诉编译器在使用模板函数时不进行名称修饰。具体步骤如下:
1. 在C++代码中声明模板函数,并使用"extern C++"关键字来告诉编译器不进行名称修饰。例如:
```
extern "C++" {
template <typename T>
void func(T t); //模板函数声明
}
```
2. 在C++代码中调用模板函数,就像调用普通的C++函数一样。例如:
```
int main() {
func<int>(1); //调用模板函数
return 0;
}
```
需要注意的是,当使用"extern C++"声明模板函数时,需要确保模板函数的定义与声明完全一致,否则会导致链接错误。同时,"extern C++"只能用于C++代码与C代码之间的互操作,不能用于C++代码与其他编程语言之间的互操作。
相关问题
template with c linkage
template with c linkage是指在C++中使用C语言的函数库时,需要使用extern "C"来声明函数,以保证C++编译器能够正确识别函数的名称和参数。这样做可以避免C++编译器对函数名进行名称修饰,从而使得C++代码能够正确地调用C语言函数库中的函数。
template specialization with C linkage
Template specialization with C linkage refers to the ability to specialize a C++ template function or class with C linkage. In C++, templates are typically resolved at compile-time, but when working with C code, it may be necessary to provide specialized template functions or classes that can be used from C.
To achieve template specialization with C linkage, you need to declare the specialized template function or class as extern "C". This tells the C++ compiler to generate the corresponding code compatible with C linkage conventions.
Here's an example of how to achieve template specialization with C linkage:
```cpp
// Template function declaration
template <typename T>
void foo(T value);
// Template specialization with C linkage
extern "C" {
// Specialization for int
template <>
void foo<int>(int value) {
// Implementation goes here
}
}
```
In the above example, the `foo` function is declared as a template function. It is then specialized for the `int` type with C linkage using the `extern "C"` declaration. The implementation of the specialized function can be provided separately.
By specializing templates with C linkage, you can ensure that the specialized functions or classes can be called from C code without any name mangling or other C++ specific features.