C++用尾插法创建一个带头节点的单链表写出代码

好的，以下是用尾插法创建一个带头节点的单链表的代码：

#include <stdio.h>
#include <stdlib.h>

typedef struct Node {
    int data;
    struct Node *next;
} Node, *LinkedList;

LinkedList createList() {
    LinkedList head = (LinkedList) malloc(sizeof(Node));
    head->next = NULL;
    return head;
}

void insert(LinkedList head, int data) {
    Node *newNode = (Node*) malloc(sizeof(Node));
    newNode->data = data;
    newNode->next = NULL;

    Node *p = head;
    while (p->next != NULL) {
        p = p->next;
    }
    p->next = newNode;
}

int main() {
    LinkedList list = createList();
    insert(list, 1);
    insert(list, 2);
    insert(list, 3);

    Node *p = list->next;
    while (p != NULL) {
        printf("%d ", p->data);
        p = p->next;
    }
    printf("\n");

    return ;
}

希望能够帮到您！