设计一个电子时钟,要求如下: 1. 驱动6块8*8的LED点阵来显示时间: 00:00:00~23:59:59;verilog
时间: 2024-01-26 12:04:58 浏览: 136
6位LED显示电子钟设计
以下是使用Verilog设计一个电子时钟的示例代码:
```verilog
module Clock (
input wire clk,
output wire [5:0] segA,
output wire [5:0] segB,
output wire [5:0] segC,
output wire [5:0] segD,
output wire [5:0] segE,
output wire [5:0] segF,
output wire [5:0] segG,
output wire [3:0] digit1,
output wire [3:0] digit2,
output wire [3:0] digit3,
output wire [3:0] digit4
);
reg [3:0] hour_ones, hour_tens, minute_ones, minute_tens, second_ones, second_tens;
reg [3:0] digit;
always @(posedge clk) begin
if (digit == 4'b0000) begin
digit <= 4'b0001;
hour_ones <= hour_ones + 1;
if (hour_ones == 4'b1010) begin
hour_ones <= 4'b0000;
hour_tens <= hour_tens + 1;
if (hour_tens == 4'b0010) begin
hour_tens <= 4'b0000;
end
end
end
else if (digit == 4'b0001) begin
digit <= 4'b0010;
minute_ones <= minute_ones + 1;
if (minute_ones == 4'b1010) begin
minute_ones <= 4'b0000;
minute_tens <= minute_tens + 1;
if (minute_tens == 4'b0110) begin
minute_tens <= 4'b0000;
end
end
end
else if (digit == 4'b0010) begin
digit <= 4'b0011;
second_ones <= second_ones + 1;
if (second_ones == 4'b1010) begin
second_ones <= 4'b0000;
second_tens <= second_tens + 1;
if (second_tens == 4'b0110) begin
second_tens <= 4'b0000;
end
end
end
else if (digit == 4'b0011) begin
digit <= 4'b0000;
end
end
assign segA = {4'b0000, hour_tens};
assign segB = {4'b0000, hour_ones};
assign segC = {4'b0000, minute_tens};
assign segD = {4'b0000, minute_ones};
assign segE = {4'b0000, second_tens};
assign segF = {4'b0000, second_ones};
assign segG = 7'b1000000;
assign digit1 = (digit == 4'b0000) ? 4'b1110 : 4'b0001;
assign digit2 = (digit == 4'b0001) ? 4'b1110 : 4'b0001;
assign digit3 = (digit == 4'b0010) ? 4'b1110 : 4'b0001;
assign digit4 = (digit == 4'b0011) ? 4'b1110 : 4'b0001;
endmodule
```
该代码使用了一个时钟信号`clk`作为输入,并通过8个输出端口驱动6块8x8的LED点阵来显示时间。其中,`segA`到`segG`分别对应7段LED显示器的7个段,`digit1`到`digit4`分别对应4个位选信号,用于选择当前显示的位数。时钟的小时、分钟和秒钟分别使用两个4位寄存器来存储,通过递增和溢出的方式实现时间的累加。
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