TypeError: list.append() takes exactly one argument (2 given)

这个错误意味着你调用了一个列表的 append() 方法，但是传递了多于一个的参数。每次调用 append() 方法时，你只能传递一个参数，即要添加到列表中的值。如果你想添加多个值，可以把它们放到一个列表或元组中，然后将该列表或元组作为 append() 方法的参数传递。请检查你的代码，找到并修复这个错误。

相关问题

TypeError: list.append() takes exactly one argument (4 given)

这个错误提示意味着您尝试在列表中使用 append() 方法时给了多个参数。请检查您的代码并确保在 append() 方法中只传递一个参数。例如，以下代码会导致类似的 TypeError:

my_list = []
my_list.append(1, 2, 3, 4)

而正确的写法应该是：

my_list = []
my_list.append(1)
my_list.append(2)
my_list.append(3)
my_list.append(4)

TypeError: list.append() takes exactly one argument (3 given)

This error occurs when you try to pass more than one argument to the `append()` method of a list. The `append()` method only takes one argument, which is the item you want to add to the end of the list.

For example, if you have a list called `my_list` and you want to add the integers 1, 2, and 3 to the end of the list, you might try to do it like this:

my_list = []
my_list.append(1, 2, 3)

However, this will result in a `TypeError` because you are passing three arguments to the `append()` method instead of just one.

To fix this error, you need to call the `append()` method once for each item you want to add to the list:

my_list = []
my_list.append(1)
my_list.append(2)
my_list.append(3)

Now the integers 1, 2, and 3 will be added to the end of the `my_list` list, and you will not get a `TypeError`.