根据我所问的上一个问题生成的代码，以菜单形式完成下面几个的输出：1.打印二叉树的构造过程；2.打印公式的后缀形式；3.二叉树的后序遍历序列；4.输入每个变量的值，计算并显示公式的真值，打印二叉树的评估过程；5.显示公式的真值表

好的，根据您的需求，我来为您完成相应的代码：

1. 打印二叉树的构造过程

class Node:
    def __init__(self, val):
        self.left = None
        self.right = None
        self.val = val

def build_tree(expression):
    stack = []
    for char in expression:
        if char.isalpha():
            node = Node(char)
            stack.append(node)
        else:
            node = Node(char)
            node.right = stack.pop()
            node.left = stack.pop()
            stack.append(node)
    return stack.pop()

def print_tree(node, level=0):
    if node:
        print(' ' * level + str(node.val))
        print_tree(node.left, level + 1)
        print_tree(node.right, level + 1)

2. 打印公式的后缀形式

def infix_to_postfix(expression):
    stack = []
    postfix_list = []
    precedence = {'(': 0, 'or': 1, 'and': 2, 'not': 3}
    for char in expression:
        if char.isalpha():
            postfix_list.append(char)
        elif char == '(':
            stack.append(char)
        elif char == ')':
            top_token = stack.pop()
            while top_token != '(':
                postfix_list.append(top_token)
                top_token = stack.pop()
        else:
            while stack and precedence[stack[-1]] >= precedence[char]:
                postfix_list.append(stack.pop())
            stack.append(char)
    while stack:
        postfix_list.append(stack.pop())
    return " ".join(postfix_list)

3. 二叉树的后序遍历序列

def postorder_traversal(node):
    if node:
        postorder_traversal(node.left)
        postorder_traversal(node.right)
        print(node.val, end=' ')

4. 输入每个变量的值，计算并显示公式的真值，打印二叉树的评估过程

def evaluate(node, var_dict):
    if node.val.isalpha():
        return var_dict.get(node.val)
    else:
        if node.val == 'not':
            return not evaluate(node.right, var_dict)
        elif node.val == 'and':
            return evaluate(node.left, var_dict) and evaluate(node.right, var_dict)
        elif node.val == 'or':
            return evaluate(node.left, var_dict) or evaluate(node.right, var_dict)

def evaluate_expression(expression):
    tree = build_tree(expression)
    var_dict = {}
    for var in set([char for char in expression if char.isalpha()]):
        value = input(f"Enter the value for {var}: ")
        var_dict[var] = bool(int(value))
    print_tree(tree)
    result = evaluate(tree, var_dict)
    print(f"The result is: {result}")

5. 显示公式的真值表

def generate_truth_table(expression):
    variables = sorted(set([char for char in expression if char.isalpha()]))
    print(" ".join(variables) + " | Result")
    print("-" * (len(variables) * 2 + 8))
    for i in range(2 ** len(variables)):
        var_dict = {}
        binary = bin(i)[2:].zfill(len(variables))
        for j, var in enumerate(variables):
            var_dict[var] = bool(int(binary[j]))
        result = evaluate(build_tree(expression), var_dict)
        print(" ".join(binary) + f" | {int(result)}")

以上就是根据您的需求所提供的代码，希望能够帮到您！