扑克游戏 憋七 代码
时间: 2024-04-07 18:26:40 浏览: 13
憋七是一种扑克牌游戏,也被称为"黑桃七"或"黑七"。它是一种多人游戏,通常由2到8名玩家参与。下面是一个简单的憋七游戏的代码示例:
```python
import random
# 初始化一副扑克牌
suits = ['♠', '♥', '♦', '♣']
ranks = ['A', '2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K']
deck = [suit + rank for suit in suits for rank in ranks]
# 洗牌
random.shuffle(deck)
# 发牌
players = []
num_players = int(input("请输入玩家数量:"))
for i in range(num_players):
player_name = input("请输入玩家{}的名字:".format(i+1))
players.append({'name': player_name, 'cards': []})
for i in range(7):
for player in players:
card = deck.pop()
player['cards'].append(card)
# 游戏开始
current_player = 0
while True:
player = players[current_player]
print("轮到玩家{}出牌".format(player['name']))
print("你的手牌:", player['cards'])
card_to_play = input("请选择要出的牌:")
if card_to_play not in player['cards']:
print("你没有这张牌,请重新选择!")
continue
player['cards'].remove(card_to_play)
print("玩家{}出牌:{}".format(player['name'], card_to_play))
if len(player['cards']) == 0:
print("玩家{}获胜!".format(player['name']))
break
current_player = (current_player + 1) % num_players
```
这段代码实现了一个简单的憋七游戏,包括洗牌、发牌和出牌的逻辑。玩家可以依次出牌,直到有玩家手中的牌全部出完,该玩家获胜。