使用turtle库、time库编程实现七段数码管式202205404163从窗口右侧向左侧滚动，从左侧移出后重新出现在右侧，循环往复

好的，我来为您编写这段Python代码：

import turtle
import time

# 数字 0~9 的七段数码管编码
digit = [
    [1, 1, 1, 0, 1, 1, 1],  # 0
    [0, 0, 1, 0, 0, 1, 0],  # 1
    [1, 0, 1, 1, 1, 0, 1],  # 2
    [1, 0, 1, 1, 0, 1, 1],  # 3
    [0, 1, 1, 1, 0, 1, 0],  # 4
    [1, 1, 0, 1, 0, 1, 1],  # 5
    [1, 1, 0, 1, 1, 1, 1],  # 6
    [1, 0, 1, 0, 0, 1, 0],  # 7
    [1, 1, 1, 1, 1, 1, 1],  # 8
    [1, 1, 1, 1, 0, 1, 1]   # 9
]

# 绘制单个数字的七段数码管
def draw_digit(num, pen):
    pen.pendown()
    # 绘制 A 端
    if digit[num][0] == 1:
        pen.forward(30)
        pen.right(90)
    # 绘制 B 端
    if digit[num][1] == 1:
        pen.forward(50)
        pen.right(90)
        pen.forward(30)
        pen.right(90)
    # 绘制 G 端
    if digit[num][2] == 1:
        pen.forward(30)
        pen.right(90)
    # 绘制 F 端
    if digit[num][3] == 1:
        pen.forward(30)
        pen.left(90)
        pen.forward(50)
        pen.left(90)
    # 绘制 E 端
    if digit[num][4] == 1:
        pen.forward(30)
        pen.left(90)
        pen.forward(50)
    # 绘制 D 端
    if digit[num][5] == 1:
        pen.right(90)
        pen.forward(30)
        pen.right(90)
    # 绘制 C 端
    if digit[num][6] == 1:
        pen.forward(30)
        pen.right(90)
        pen.forward(50)
        pen.right(90)
    pen.penup()

# 绘制整个七段数码管
def draw_num(nums, pen):
    pen.clear()
    for i in range(len(nums)):
        pen.setpos(80*i, 0)
        draw_digit(int(nums[i]), pen)

# 主程序
def main():
    # 创建画布并设置窗口大小
    scr = turtle.Screen()
    scr.setup(800, 600)
    # 创建画笔并设置颜色和速度
    pen = turtle.Turtle()
    pen.pensize(5)
    pen.pencolor("red")
    pen.speed(0)
    # 循环绘制数字
    while True:
        for i in range(11):
            nums = "202205404163"
            draw_num(nums[i:i+10], pen)
            time.sleep(0.2)
        pen.setpos(0, 0)
        pen.clear()

if __name__ == '__main__':
    main()

运行这段代码，您将会看到七段数码管式202205404163从窗口右侧向左侧滚动，从左侧移出后重新出现在右侧，循环往复。