就是小游戏代码用c语言写
时间: 2023-06-04 22:08:12 浏览: 228
非常好的问题!我可以给您提供一些关于用C语言编写小游戏代码的资源和教程。首先,您可以阅读一些C语言编程书籍,比如《C Primer Plus》和《C语言经典100例》。此外,您还可以在网上搜索一些C语言小游戏的代码示例和教程,例如tetris、扫雷、2048等。另外,您可以参考一些开源的C语言游戏引擎,例如Allegro和SDL,它们可以帮助您更快速地编写游戏。希望这些资源对您有所帮助!
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用c语言写一个扫雷小游戏 代码
以下是一个简单的扫雷游戏的C语言代码示例:
```c
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define ROWS 10
#define COLS 10
#define MINES 10
int main() {
int board[ROWS][COLS] = {0}; // 游戏棋盘
int displayBoard[ROWS][COLS] = {0}; // 显示棋盘,存储玩家已经翻开的方块
int row, col, minesLeft, gameOver;
int i, j;
// 随机生成地雷
srand(time(NULL)); // 初始化随机数种子
minesLeft = MINES;
while (minesLeft > 0) {
row = rand() % ROWS;
col = rand() % COLS;
if (board[row][col] == 0) {
board[row][col] = 1;
minesLeft--;
}
}
gameOver = 0;
while (!gameOver) {
// 显示游戏棋盘
printf(" ");
for (i = 0; i < COLS; i++) {
printf("%d ", i);
}
printf("\n");
for (i = 0; i < ROWS; i++) {
printf("%d ", i);
for (j = 0; j < COLS; j++) {
if (displayBoard[i][j] == 0) {
printf(". ");
} else if (displayBoard[i][j] == 1) {
if (board[i][j] == 1) {
printf("* ");
} else {
printf("%d ", countMines(board, i, j));
}
}
}
printf("\n");
}
printf("Mines left: %d\n", minesLeft);
// 玩家选择翻开哪个方块
printf("Enter row and column: ");
scanf("%d %d", &row, &col);
// 检查翻开的方块是否合法
if (row < 0 || row >= ROWS || col < 0 || col >= COLS) {
printf("Invalid input!\n");
} else if (displayBoard[row][col] == 1) {
printf("Already flipped!\n");
} else {
// 翻开方块
displayBoard[row][col] = 1;
if (board[row][col] == 1) {
printf("Game over! You hit a mine!\n");
gameOver = 1;
} else {
// 如果翻开的方块周围没有地雷,自动翻开周围的方块
if (countMines(board, row, col) == 0) {
autoFlip(displayBoard, board, row, col);
}
// 检查是否已经胜利
if (countFlipped(displayBoard) == ROWS * COLS - MINES) {
printf("Congratulations! You win!\n");
gameOver = 1;
}
}
}
}
return 0;
}
// 计算一个方块周围的地雷数量
int countMines(int board[ROWS][COLS], int row, int col) {
int count = 0;
int i, j;
for (i = row - 1; i <= row + 1; i++) {
for (j = col - 1; j <= col + 1; j++) {
if (i >= 0 && i < ROWS && j >= 0 && j < COLS && board[i][j] == 1) {
count++;
}
}
}
return count;
}
// 自动翻开一个方块周围的方块
void autoFlip(int displayBoard[ROWS][COLS], int board[ROWS][COLS], int row, int col) {
int i, j;
for (i = row - 1; i <= row + 1; i++) {
for (j = col - 1; j <= col + 1; j++) {
if (i >= 0 && i < ROWS && j >= 0 && j < COLS && displayBoard[i][j] == 0) {
displayBoard[i][j] = 1;
if (board[i][j] == 0) {
autoFlip(displayBoard, board, i, j);
}
}
}
}
}
// 计算已翻开的方块数量
int countFlipped(int displayBoard[ROWS][COLS]) {
int count = 0;
int i, j;
for (i = 0; i < ROWS; i++) {
for (j = 0; j < COLS; j++) {
if (displayBoard[i][j] == 1) {
count++;
}
}
}
return count;
}
```
这个扫雷游戏使用10x10的棋盘,包含10个地雷。玩家可以选择翻开棋盘上的某个方块,如果翻开的方块是地雷,则游戏结束;否则,游戏继续进行。如果翻开的方块周围没有地雷,则自动翻开周围的方块。当所有非地雷方块都被翻开时,玩家获胜。
c语言写贪吃蛇小游戏代码
贪吃蛇是一种经典的小游戏,以下是C语言实现贪吃蛇小游戏的代码:
```
#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <windows.h>
#define WIDTH 30
#define HEIGHT 20
#define SNAKE_MAX_LENGTH 100
int score = 0;
int speed = 200;
typedef struct _COORD {
int x;
int y;
} COORD;
typedef struct _SNAKE {
COORD body[SNAKE_MAX_LENGTH];
int length;
int direction;
} SNAKE;
typedef struct _FOOD {
COORD position;
} FOOD;
void gotoxy(int x, int y) {
COORD pos = {x, y};
HANDLE hOut = GetStdHandle(STD_OUTPUT_HANDLE);
SetConsoleCursorPosition(hOut, pos);
}
void drawBorder() {
int i;
for (i = 0; i < WIDTH + 2; i++) {
printf("#");
}
printf("\n");
for (i = 0; i < HEIGHT; i++) {
printf("#");
gotoxy(WIDTH + 1, i + 1);
printf("#");
}
printf("\n");
for (i = 0; i < WIDTH + 2; i++) {
printf("#");
}
printf("\n");
}
void initSnake(SNAKE *snake) {
snake->length = 3;
snake->direction = 'd';
snake->body[0].x = 5;
snake->body[0].y = 3;
snake->body[1].x = 4;
snake->body[1].y = 3;
snake->body[2].x = 3;
snake->body[2].y = 3;
}
void drawSnake(SNAKE *snake) {
int i;
for (i = 0; i < snake->length; i++) {
gotoxy(snake->body[i].x, snake->body[i].y);
printf("*");
}
}
void moveSnake(SNAKE *snake) {
int i;
for (i = snake->length - 1; i > 0; i--) {
snake->body[i].x = snake->body[i - 1].x;
snake->body[i].y = snake->body[i - 1].y;
}
switch (snake->direction) {
case 'w':
snake->body[0].y--;
break; case 's':
snake->body[0].y++;
break;
case 'a':
snake->body[0].x--;
break;
case 'd':
snake->body[0].x++;
break;
}
}
void generateFood(FOOD *food, SNAKE *snake) {
int x, y;
do {
x = rand() % WIDTH + 1;
y = rand() % HEIGHT + 1;
} while (isSnake(snake, x, y));
food->position.x = x;
food->position.y = y;
}
void drawFood(FOOD *food) {
gotoxy(food->position.x, food->position.y);
printf("@");
}
int isSnake(SNAKE *snake, int x, int y) {
int i;
for (i = 0; i < snake->length; i++) {
if (snake->body[i].x == x && snake->body[i].y == y) {
return 1;
}
}
return 0;
}
int isHitWall(SNAKE *snake) {
if (snake->body[0].x == 0 || snake->body[0].x == WIDTH + 1 || snake->body[0].y == 0 || snake->body[0].y == HEIGHT + 1) {
return 1;
}
return 0;
}
int isEatFood(SNAKE *snake, FOOD *food) {
if (snake->body[0].x == food->position.x && snake->body[0].y == food->position.y) {
return 1;
}
return 0;
}
void updateScore() {
gotoxy(WIDTH + 5, 5);
printf("Score: %d", score);
}
void updateSpeed() {
gotoxy(WIDTH + 5, 6);
printf("Speed: %d", speed);
}
void gameOver() {
system("cls");
printf("Game Over!\n");
printf("Your score is %d\n", score);
exit(0);
}
int main() {
SNAKE snake;
FOOD food;
srand(time(NULL));
initSnake(&snake);
generateFood(&food, &snake);
drawBorder();
drawSnake(&snake);
drawFood(&food);
while (1) {
if (_kbhit()) {
char ch = _getch();
switch (ch) {
case 'w':
case 's':
case 'a':
case 'd':
if (abs(ch - snake.direction) != 2) {
snake.direction = ch;
}
break;
case 'q':
gameOver();
break;
}
}
moveSnake(&snake);
if (isHitWall(&snake) || isSnake(&snake, snake.body[0].x, snake.body[0].y)) {
gameOver();
}
if (isEatFood(&snake, &food)) {
snake.length++;
score += 10;
speed -= 10;
if (speed < 50) {
speed = 50;
}
generateFood(&food, &snake);
updateScore();
updateSpeed();
}
system("cls");
drawBorder();
drawSnake(&snake);
drawFood(&food);
Sleep(speed);
}
return 0;
}
```