编程实现一个由7个元素组成的整数数组，存放在主存的连续存储单元中，数组的起始地址为AS。AS{31h,36h,33h,32h,38h,37h,35h}1. 编程实现：将数组AS中的元素向右循环移动一个位置，例如移位后变成{35h,31h,36h,33h,32h,38h,37h}2. 编程实现：将AS中最大元素和最小元素分别存于Max和Min中3. 将字符串AS中的内容复制到target中，并显示输出

1.

#include <stdio.h>

int main() {
    int AS[] = {0x31, 0x36, 0x33, 0x32, 0x38, 0x37, 0x35};
    int temp = AS[6];
    for (int i = 6; i > 0; i--) {
        AS[i] = AS[i - 1];
    }
    AS[0] = temp;
    for (int i = 0; i < 7; i++) {
        printf("%x ", AS[i]);
    }
    return 0;
}

2.

#include <stdio.h>

int main() {
    int AS[] = {0x31, 0x36, 0x33, 0x32, 0x38, 0x37, 0x35};
    int min = AS[0], max = AS[0];
    for (int i = 1; i < 7; i++) {
        if (AS[i] > max) {
            max = AS[i];
        }
        if (AS[i] < min) {
            min = AS[i];
        }
    }
    printf("Max: %x\n", max);
    printf("Min: %x\n", min);
    return 0;
}

3.

#include <stdio.h>
#include <string.h>

int main() {
    char AS[] = {0x31, 0x36, 0x33, 0x32, 0x38, 0x37, 0x35, '\0'};
    char target[8];
    strcpy(target, AS);
    printf("%s", target);
    return 0;
}