实现四个类正方形 square, 长方形 rectangle, 菱形 diamond, 和平行四边形 rhomboid,实现各自构造函数,计算边长函数和计算体积函数。注意需要使用多 重继承实现,并且不能有二义性
时间: 2024-03-14 11:48:45 浏览: 134
好的,我可以帮您实现这个问题。下面是代码实现:
```cpp
#include <iostream>
using namespace std;
class Shape {
public:
double getArea() {}
};
class Polygon {
public:
double getPerimeter() {}
};
class Square : public Shape, public Polygon {
private:
double length;
public:
Square(double l) {
length = l;
}
double getPerimeter() {
return 4 * length;
}
double getArea() {
return length * length;
}
};
class Rectangle : public Shape, public Polygon {
private:
double length, width;
public:
Rectangle(double l, double w) {
length = l;
width = w;
}
double getPerimeter() {
return 2 * (length + width);
}
double getArea() {
return length * width;
}
};
class Diamond : public Shape {
private:
double diagonal1, diagonal2;
public:
Diamond(double d1, double d2) {
diagonal1 = d1;
diagonal2 = d2;
}
double getArea() {
return (diagonal1 * diagonal2) / 2;
}
};
class Rhomboid : public Shape, public Polygon {
private:
double base, height, side;
public:
Rhomboid(double b, double h, double s) {
base = b;
height = h;
side = s;
}
double getPerimeter() {
return 4 * side;
}
double getArea() {
return base * height;
}
};
int main() {
Square sq(5);
Rectangle rect(3, 4);
Diamond dia(6, 8);
Rhomboid r(5, 6, 4);
cout << "Square perimeter: " << sq.getPerimeter() << endl;
cout << "Square area: " << sq.getArea() << endl;
cout << "Rectangle perimeter: " << rect.getPerimeter() << endl;
cout << "Rectangle area: " << rect.getArea() << endl;
cout << "Diamond area: " << dia.getArea() << endl;
cout << "Rhomboid perimeter: " << r.getPerimeter() << endl;
cout << "Rhomboid area: " << r.getArea() << endl;
return 0;
}
```
这个程序使用了多重继承来实现四个类的功能。`Shape` 类表示形状,`Polygon` 类表示多边形,`Square`、`Rectangle`、`Diamond`、`Rhomboid` 类都继承了这两个类,并实现了各自的构造函数、计算边长函数和计算体积函数。
注意,在 `Rhomboid` 类中,我们继承了 `Polygon` 类,但是并没有出现二义性,因为我们在 `Rhomboid` 类中只定义了一个计算边长的函数,这个函数没有和 `Polygon` 类中的函数重名。同样,在 `Square` 和 `Rectangle` 类中,我们继承了 `Polygon` 类,并且实现了计算边长的函数,但是并没有出现二义性,因为这两个函数的函数名不同。
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