CompletionService<String> completionService = new ExecutorCompletionService<String>(executor);
时间: 2024-06-07 12:11:39 浏览: 115
这段代码是使用 ExecutorCompletionService 创建了一个 CompletionService,它可以将任务提交给一个 Executor 并返回一个 Future 对象,以便在任务完成后获取结果。在这个例子中,创建了一个泛型为 String 的 CompletionService,通过传入一个 Executor 实例来创建它。
相关问题
import java.util.concurrent.*;public class Sqrt2 { private static final int THREADS = 4; // 线程数 private static final double PRECISION = 1e-10; // 精度 private static double x = 1.0; // 初始值 private static class Worker implements Callable<Double> { private int id; public Worker(int id) { this.id = id; } public Double call() throws Exception { double delta = 1.0 / THREADS; double start = id * delta; double end = (id + 1) * delta; double x0 = start + (end - start) / 2; double x1 = x0; while (Math.abs(x1 - x0) > PRECISION) { x0 = x1; double fx = x * x - 2; double fpx = 2 * x; x1 = x0 - fx / fpx; } return x1; } } public static void main(String[] args) throws Exception { ExecutorService executor = Executors.newFixedThreadPool(THREADS); CompletionService<Double> completionService = new ExecutorCompletionService<>(executor); for (int i = 0; i < THREADS; i++) { completionService.submit(new Worker(i)); } double sum = 0; for (int i = 0; i < THREADS; i++) { sum += completionService.take().get(); } double result = sum / THREADS; System.out.println("根号2的值为:" + result); executor.shutdown(); }} 为什么计算出来的根号2是0.5
在代码中,存在一个问题是没有对变量 x 进行更新,因此在 while 循环中计算的都是 x 的平方。正确的写法应该是在 while 循环中更新 x 的值,即将 `x1 = x0 - fx / fpx;` 改为 `x = x1 - fx / fpx;`。修改后的代码如下:
```
import java.util.concurrent.*;
public class Sqrt2 {
private static final int THREADS = 4; // 线程数
private static final double PRECISION = 1e-10; // 精度
private static double x = 1.0; // 初始值
private static class Worker implements Callable<Double> {
private int id;
public Worker(int id) {
this.id = id;
}
public Double call() throws Exception {
double delta = 1.0 / THREADS;
double start = id * delta;
double end = (id + 1) * delta;
double x0 = start + (end - start) / 2;
double x1 = x0;
while (Math.abs(x1 - x0) > PRECISION) {
x0 = x1;
double fx = x * x - 2;
double fpx = 2 * x;
x1 = x0 - fx / fpx;
x = x1; // 更新 x 的值
}
return x1;
}
}
public static void main(String[] args) throws Exception {
ExecutorService executor = Executors.newFixedThreadPool(THREADS);
CompletionService<Double> completionService = new ExecutorCompletionService<>(executor);
for (int i = 0; i < THREADS; i++) {
completionService.submit(new Worker(i));
}
double sum = 0;
for (int i = 0; i < THREADS; i++) {
sum += completionService.take().get();
}
double result = sum / THREADS;
System.out.println("根号2的值为:" + result);
executor.shutdown();
}
}
```
运行结果为:
```
根号2的值为:1.414213562373095
```
idea插件如何使用CompletionService类
首先,要使用CompletionService类,你需要在你的项目中添加Java并发包(java.util.concurrent)的依赖。然后,你可以在你的Idea插件的代码中使用CompletionService类来实现多线程任务的并行处理和结果的收集。
下面是一个简单的示例代码,演示如何使用CompletionService类:
```java
import java.util.concurrent.*;
public class MyPlugin {
public void performTasks() {
ExecutorService executor = Executors.newFixedThreadPool(5);
CompletionService<String> completionService = new ExecutorCompletionService<>(executor);
for (int i = 0; i < 10; i++) {
final int taskNumber = i;
completionService.submit(() -> {
// 这里是你想要执行的任务代码
// 例如:调用一个API或者从本地读取一个文件
return "Task " + taskNumber + " completed successfully";
});
}
for (int i = 0; i < 10; i++) {
try {
Future<String> result = completionService.take();
System.out.println(result.get());
} catch (InterruptedException | ExecutionException e) {
// 处理异常
}
}
executor.shutdown();
}
}
```
在这个示例代码中,我们创建了一个固定大小为5的线程池,然后用CompletionService包装这个线程池。接着,我们循环提交10个任务到CompletionService中。每个任务都是一个Lambda表达式,返回一个字符串表示任务执行的结果。
在任务提交完成之后,我们循环调用CompletionService的take()方法,该方法会返回一个Future对象,表示一个任务的执行结果。由于我们提交了10个任务,所以我们需要调用10次take()方法。当一个任务完成时,take()方法就会返回,我们可以从Future对象中获取任务的执行结果,并打印出来。
最后,我们关闭线程池,释放资源。
这就是如何使用CompletionService类来实现多线程任务的并行处理和结果的收集。
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