select a.*, b.name activityName, c.name productName, c.member_max memberMax, d.status as complete, group_concat(if(e.face_value is null, "", e.face_value) separator "\n") as rewardAmount, group_concat(if(e.coupon_code is null, "", e.coupon_code ) separator "\n") as couponCode , group_concat(if(e.coupon_id is null, "", e.coupon_id) separator "\n") as caId from marketing_group_tool_group_member a left join marketing_group_tool_group_info d on a.group_id = d.id left join marketing_group_tool_activity b on a.activity_id = b.activity_id left join marketing_group_tool_product_base c on a.product_id = c.product_id left join marketing_group_tool_send_coupon_record e on (a.group_id = e.group_id and a.card_no = e.card_no) left join wx_recommend_organization organization on b.organization_id = organization.id where ((organization.tree_id between 2002000000000000 and 2002999999999999) or (organization.tree_id between 1000000000000000 and 1999999999999999) or (organization.tree_id between 2000000000000000 and 2999999999999999) or (organization.tree_id between 3000000000000000 and 3999999999999999) or (organization.tree_id between 4000000000000000 and 4999999999999999) or (organization.tree_id between 6000000000000000 and 6999999999999999) or (organization.tree_id between 5000000000000000 and 5999999999999999) or (organization.tree_id between 10000000000000000 and 10999999999999999) or (organization.tree_id between 8000000000000000 and 8999999999999999) or (organization.tree_id between 9000000000000000 and 9999999999999999) or (organization.tree_id between 11000000000000000 and 11999999999999999) or (organization.tree_id between 12000000000000000 and 12999999999999999) or (organization.tree_id between 13000000000000000 and 13999999999999999) or (organization.tree_id between 14000000000000000 and 14999999999999999) or (organization.tree_id between 15000000000000000 and 15999999999999999) or (organization.tree_id between 16000000000000000 and 16999999999999999) or (organization.tree_id between 17000000000000000 and 17999999999999999) ) and 1 = 1 group by a.id, a.activity_id , a.group_id , a.product_id , a.activity_referral_code, a.product_referral_code , a.openid , a.unionid , a.nickname , a.head_img , a.mobile , a.is_sub_buy , a.is_sub_progress , a.is_sub_success , a.sort , a.card_no , a.create_time , a.is_received_notice , a.is_received_progress , a.is_received_success , b.name, c.name, c.member_max , d.status order by a.id desc limit 0,20;

这是一个比较复杂的 SQL 查询语句，有很多连表和条件。要想对其进行优化，需要结合具体的环境和数据情况进行分析。

这里提供一些常见的 SQL 优化建议：

1. 确保表上有合适的索引，包括主键、唯一键和常用查询条件的索引，可以通过 `explain` 命令来查看查询计划和索引使用情况。

2. 避免使用 `select *`，只选择需要的字段，可以减少数据量和网络传输开销。

3. 尽量避免使用 `group_concat`，这会导致 MySQL 在内部生成临时表，会消耗大量的内存和 CPU 时间，可以考虑在应用层进行拼接。

4. 将复杂查询拆分成多个简单查询，每个查询只涉及少量表和字段，可以利用缓存和减轻数据库负担。

5. 对于复杂的查询条件，可以考虑使用全文索引、分词和搜索引擎等技术，以提高查询效率和准确性。

总之，SQL 优化需要根据具体情况进行分析和实践，需要综合考虑数据量、表结构、索引设计、查询条件等多个因素。

相关问题

select b.*,p.id as p_id,p.id,p.proCode,p.proName from smbms.smbms_bill b,smbms_provider p where b.productName like CONCAT('%',#{productName},'%') and b.providerId = #{providerId} and b.isPayment = #{isPayment} and b.providerId = p.id

你想查询 smbms_bill 表和 smbms_provider 表，并根据条件进行筛选，对吗？你希望将账单的所有信息和对应的供应商信息一起返回，是吗？

以下是你提供的 SQL 查询语句：

SELECT b.*, p.id AS p_id, p.id, p.proCode, p.proName
FROM smbms.smbms_bill b, smbms_provider p
WHERE b.productName LIKE CONCAT('%', #{productName}, '%')
  AND b.providerId = #{providerId}
  AND b.isPayment = #{isPayment}
  AND b.providerId = p.id

在这个查询中，我注意到你使用了 `CONCAT` 函数来拼接模糊查询的条件，并且通过别名将供应商的 ID 字段命名为 `p_id`，以避免与账单中的 ID 字段冲突。同时，你在查询条件中使用了占位符（`#{}`）来接收参数值。

请确保在执行查询之前，将占位符中的参数值正确地设置为实际的值。

function getPagedList(contractId) { var contractId = body.param.contractId; var sql = ` SELECT a.id, a.contract_id contractId, a.product_id productId, a.purchase_num purchaseNum, a.purchase_price purchasePrice, a.remark, b.product_name productName, b.spec_code specCode, c.type_name typeName, d.unitcode unitCode FROM mes214820519.wms_pur_list_214820519 a, mes214820519.wms_product_214820519 b, mes214820519.wms_product_class_214820519 c, mes214820519.wms_unit_code_214820519 d WHERE a.product_id=b.id AND b.product_class_id = c.id AND b.unit_code_id=d.id AND a.contract_id=#{contractId}`; return db.pager(sql, {contractId: contractId}) } 用JavaScript语言修改这段代码

function getPagedList(contractId) {
var sql = `SELECT
a.id,
a.contract_id as contractId,
a.product_id as productId,
a.purchase_num as purchaseNum,
a.purchase_price as purchasePrice,
a.remark,
b.product_name as productName,
b.spec_code as specCode,
c.type_name as typeName,
d.unitcode as unitCode
FROM
mes214820519.wms_pur_list_214820519 a
INNER JOIN mes214820519.wms_product_214820519 b
ON a.product_id = b.id
INNER JOIN mes214820519.wms_product_class_214820519 c
ON b.product_class_id = c.id
INNER JOIN mes214820519.wms_unit_code_214820519 d
ON b.unit_code_id = d.id
WHERE
a.contract_id = :contractId`;
return db.pager(sql, { contractId: contractId });
}

在修改后的代码中，我使用了ES6模板字符串来构建SQL语句，同时使用了INNER JOIN来连接多张表，使代码更加简洁易读。另外，我还使用了命名参数代替了原来的占位符，以提高代码的可读性和可维护性。