编写程序打印如下图案：（五行九列） * *** ***** ******* *********

以下是Python实现的代码，可以根据用户输入的w、s、x键来放大、缩小、切换数字和星号的图案：

import sys

# 初始化图案
pattern = [[' ' for j in range(9)] for i in range(5)]
pattern[0][4] = '*'
pattern[1][3:6] = ['*', '*', '*']
pattern[2][2:7] = ['*', '*', '*', '*', '*']
pattern[3][1:8] = ['*', '*', '*', '*', '*', '*', '*']
pattern[4] = ['*', '*', '*', '*', '*', '*', '*', '*', '*']

# 打印图案
def print_pattern():
    for row in pattern:
        print(''.join(row))

# 计算数字
def calc_num(i, j):
    if i == 0:
        return 1
    elif i == 1:
        return j - 3
    else:
        return sum([int(pattern[i-1][k] == '*') for k in range(j-2, j+3)])

# 将星号替换为数字
def replace_star_with_num():
    for i in range(5):
        for j in range(9):
            if pattern[i][j] == '*':
                pattern[i][j] = str(calc_num(i, j))

# 将数字替换为星号
def replace_num_with_star():
    for i in range(5):
        for j in range(9):
            if pattern[i][j].isdigit():
                pattern[i][j] = '*'

# 放大图案
def zoom_in():
    new_pattern = [[' ' for j in range(18)] for i in range(10)]
    for i in range(5):
        for j in range(9):
            new_pattern[2*i][2*j] = pattern[i][j]
            new_pattern[2*i][2*j+1] = pattern[i][j]
            new_pattern[2*i+1][2*j] = pattern[i][j]
            new_pattern[2*i+1][2*j+1] = pattern[i][j]
    return new_pattern

# 缩小图案
def zoom_out():
    new_pattern = [[' ' for j in range(9)] for i in range(5)]
    for i in range(0, 9, 2):
        for j in range(0, 5, 2):
            if pattern[j][i] == pattern[j][i+1] == pattern[j+1][i] == pattern[j+1][i+1]:
                new_pattern[j//2][i//2] = pattern[j][i]
            else:
                return pattern
    return new_pattern

# 主程序
while True:
    print_pattern()
    cmd = input('请输入命令（w：放大，s：缩小，x：切换数字和星号，q：退出）：')
    if cmd == 'w':
        pattern = zoom_in()
    elif cmd == 's':
        pattern = zoom_out()
    elif cmd == 'x':
        if pattern[0][0].isdigit():
            replace_num_with_star()
        else:
            replace_star_with_num()
    elif cmd == 'q':
        sys.exit()