编程实现：输入若干个正整数（输入-1为结束标志），建立一个单向链表，将其中的偶数值结点删除后输出。链表节点定义为： struct Node{ int data; struct Node *next; }用c语言写代码

好的，以下是C语言代码实现：

#include <stdio.h>
#include <stdlib.h>

struct Node{
    int data;
    struct Node* next;
};

void deleteEvenNodes(struct Node** headRef){
    struct Node* current = *headRef;
    struct Node* prev = NULL;
    
    while(current != NULL){
        if(current->data % 2 == 0){
            if(prev == NULL){
                *headRef = current->next;
                free(current);
                current = *headRef;
            }
            else{
                prev->next = current->next;
                free(current);
                current = prev->next;
            }
        }
        else{
            prev = current;
            current = current->next;
        }
    }
}

void printList(struct Node* head){
    struct Node* current = head;
    
    while(current != NULL){
        printf("%d ", current->data);
        current = current->next;
    }
    printf("\n");
}

int main(){
    struct Node* head = NULL;
    struct Node* tail = NULL;
    int data;
    
    printf("请输入若干个正整数，以-1结束：\n");
    scanf("%d", &data);
    
    while(data != -1){
        struct Node* newNode = (struct Node*)malloc(sizeof(struct Node));
        newNode->data = data;
        newNode->next = NULL;
        
        if(head == NULL){
            head = newNode;
            tail = newNode;
        }
        else{
            tail->next = newNode;
            tail = newNode;
        }
        scanf("%d", &data);
    }
    
    deleteEvenNodes(&head);
    printList(head);
    
    return 0;
}

输入样例：

请输入若干个正整数，以-1结束：
1 2 3 4 5 6 -1

输出样例：

1 3 5