如何在下面这段函数中给nv值限制在nu <= 0 or nu > 1的取值范围内:# 定义适应度评价函数,使用交叉验证计算准确率 def evaluate(individual): clf.set_params(kernel='rbf', gamma=individual[0], nu=individual[1]) accuracy = 0 for i in range(5): X_train, X_test = train_test_split(X_TRAIN, test_size=0.2) clf.fit(X_train) accuracy += clf.score(X_test) return accuracy / 5,
时间: 2023-06-06 22:09:07 浏览: 38
可以使用if语句进行判断,若nu的取值不在规定范围内,则将nv的值赋为0或1。修改后的代码如下:
```python
def f(nu):
if nu <= 0:
nv = 0
elif nu > 1:
nv = 1
else:
nv = nu**2
return nv
```
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如何在下面这段函数中添加:给nv值限制在nu <= 0 or nu > 1的取值范围内:# 定义适应度评价函数,使用交叉验证计算准确率 def evaluate(individual): clf.set_params(kernel='rbf', gamma=individual[0], nu=individual[1]) accuracy = 0 for i in range(5): X_train, X_test = train_test_split(X_TRAIN, test_size=0.2) clf.fit(X_train) accuracy += clf.score(X_test) return accuracy / 5,
要给nv值限制在nu <= 0 or nu > 1的取值范围内,可以在下面这段函数中添加以下代码:
if nv <= 0:
nv = 0
elif nv > 1:
nv = 1
这样做的意思是,如果nv小于等于0,那么将nv赋值为0;如果nv大于1,那么将nv赋值为1。这样可以保证nv的取值范围在nu <= 0 or nu > 1之内。
如何在下面的代码中给nv值限制在nu <= 0 or nu > 1:from sklearn.svm import OneClassSVM from sklearn.model_selection import train_test_split import numpy as np from deap import creator, base, tools, algorithms # 创建OneClassSVM分类器 clf = OneClassSVM() # 定义优化目标,这里使用评估分类器的准确率 creator.create("FitnessMax", base.Fitness, weights=(1.0,)) creator.create("Individual", list, fitness=creator.FitnessMax) # 定义一些算法参数 POPULATION_SIZE = 10 P_CROSSOVER = 0.9 P_MUTATION = 0.1 MAX_GENERATIONS = 50 HALL_OF_FAME_SIZE = 3 N_PARAMETER = 4 MIN_PARAM = 0.01 MAX_PARAM = 10.0 # 定义适应度评价函数,使用交叉验证计算准确率 def evaluate(individual): clf.set_params(kernel='rbf', gamma=individual[0], nu=individual[1]) accuracy = 0 for i in range(5): X_train, X_test = train_test_split(X_TRAIN, test_size=0.2) clf.fit(X_train) accuracy += clf.score(X_test) return accuracy / 5, # 定义遗传算法工具箱 toolbox = base.Toolbox() toolbox.register("attr_float", lambda: np.random.uniform(MIN_PARAM, MAX_PARAM)) toolbox.register("individual", tools.initRepeat, creator.Individual, toolbox.attr_float, n=N_PARAMETER) toolbox.register("population", tools.initRepeat, list, toolbox.individual) toolbox.register("evaluate", evaluate) toolbox.register("mate", tools.cxBlend, alpha=0.5) toolbox.register("mutate", tools.mutGaussian, mu=0, sigma=1, indpb=0.1) toolbox.register("select", tools.selTournament, tournsize=3) # 定义精英机制 hall_of_fame = tools.HallOfFame(HALL_OF_FAME_SIZE) # 运行遗传算法 population = toolbox.population(n=POPULATION_SIZE) stats = tools.Statistics(lambda ind: ind.fitness.values) stats.register("avg", np.mean) stats.register("min", np.min) stats.register("max", np.max) population, logbook = algorithms.eaSimple(population, toolbox, cxpb=P_CROSSOVER, mutpb=P_MUTATION, ngen=MAX_GENERATIONS, stats=stats, halloffame=hall_of_fame) # 输出优化结果 best_individual = tools.selBest(population, k=1)[0] best_parameters = [] for param in best_individual: best_parameters.append(round(param, 2)) print("OneClassSVM params: gamma={}, nu={}".format(*best_parameters))
可以在创建评估函数时对nv进行限制,如果nv不符合要求,则将其调整为0或1。具体实现方法为,先定义一个函数,在函数中使用if语句判断nu的取值,并将nv调整为0或1。然后在创建评估函数时,使用这个函数对nv进行限制。代码示例如下:
```python
# 定义限制函数
def limit_nv(nv, nu):
if nu <= 0:
return 0
elif nu > 1:
return 1
else:
return nv
# 创建评估函数时,对nv进行限制
def evalOneMax(individual):
nu = individual[0]
nv = individual[1]
# 将nv限制在0~1之间
nv = limit_nv(nv, nu)
# 其他评估代码
...
```
这样,就可以在代码中给nv值限制在nu <= 0 or nu > 1的取值范围内了。