用python写出给定一个手机号列表，以字典的形式输出四个运营商号码的统计结果

假设手机号列表为phone_list，以下是代码实现：

# 定义四个运营商的号码段
china_mobile = ["134", "135", "136", "137", "138", "139", "150", "151", "152", "157", "158", "159", "182", "183", "184", "187", "188"]
china_unicom = ["130", "131", "132", "155", "156", "185", "186"]
china_telecom = ["133", "153", "180", "181", "189"]
others = ["170", "171", "173", "175", "176", "177", "178", "198", "199"]

# 定义字典统计结果
result = {"China Mobile": 0, "China Unicom": 0, "China Telecom": 0, "Others": 0}

# 统计每个号码的运营商并加入结果字典
for phone in phone_list:
    if phone[:3] in china_mobile:
        result["China Mobile"] += 1
    elif phone[:3] in china_unicom:
        result["China Unicom"] += 1
    elif phone[:3] in china_telecom:
        result["China Telecom"] += 1
    else:
        result["Others"] += 1

# 输出结果字典
print(result)

解释：

首先定义了四个运营商的号码段，然后定义了一个字典result来统计结果，其中四个键分别对应四个运营商，初始值都为0。

然后使用for循环遍历手机号列表，对于每个手机号，根据前三位判断其运营商，然后将对应的结果字典的值加1。

最后输出结果字典。