用python写有16个选手进行比赛,两个选手中胜者参加下一场,负者出局,请求出最后的冠军
时间: 2024-05-07 07:17:23 浏览: 22
这是一个经典的比赛淘汰制问题,可以用二叉树来模拟。我们从第一轮开始,分别将16个选手两两配对。每场比赛的胜者晋级到下一轮,败者则被淘汰。如此进行下去,直到第四轮只剩下一名选手,即为冠军。
以下是使用Python实现的一个示例代码:
```
players = ['player1', 'player2', 'player3', 'player4', 'player5', 'player6', 'player7', 'player8',
'player9', 'player10', 'player11', 'player12', 'player13', 'player14', 'player15', 'player16']
rounds = []
rounds.append(players)
while len(rounds[-1]) > 1:
current_round = []
for i in range(0, len(rounds[-1]), 2):
winner = ''
if i+1 < len(rounds[-1]):
# play match
print(f'{rounds[-1][i]} vs {rounds[-1][i+1]}')
winner = input('Who is the winner? ')
else:
# player has no opponent in this round
winner = rounds[-1][i]
print(f'{winner} has no opponent and automatically advances to next round.')
current_round.append(winner)
rounds.append(current_round)
print(f'{rounds[-1][0]} is the Champion!')
```
这个代码将`players`列表中的选手两两配对,并逐轮淘汰,最终找出冠军。在每轮比赛中,程序会提示输入获胜者的名字,并把名字放到一个新的列表中作为下一轮的参赛者。最后,程序输出最终获胜者的名字。