写一个穿越火线锁头c文件
时间: 2024-02-01 11:17:30 浏览: 91
以下是一个简单的穿越火线锁头C语言程序:
```c
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define MAP_SIZE 9
#define CHESS_EMPTY 0
#define CHESS_PLAYER1 1
#define CHESS_PLAYER2 2
int map[MAP_SIZE][MAP_SIZE];
int player;
int row, col;
int gameOver = 0;
void initMap(){
for(int i = 0; i < MAP_SIZE; i++){
for(int j = 0; j < MAP_SIZE; j++){
map[i][j] = CHESS_EMPTY;
}
}
}
void drawMap(){
printf(" ");
for(int i = 0; i < MAP_SIZE; i++){
printf("%d ", i);
}
printf("\n");
for(int i = 0; i < MAP_SIZE; i++){
printf("%2d ", i);
for(int j = 0; j < MAP_SIZE; j++){
switch(map[i][j]){
case CHESS_EMPTY:
printf(". ");
break;
case CHESS_PLAYER1:
printf("O ");
break;
case CHESS_PLAYER2:
printf("X ");
break;
}
}
printf("\n");
}
}
void input(){
printf("Player %d's turn\n", player);
printf("Enter row and column (e.g. 2 3): ");
scanf("%d %d", &row, &col);
}
void placeChess(){
if(map[row][col] == CHESS_EMPTY){
map[row][col] = player;
int count = 0;
for(int i = -1; i <= 1; i++){
for(int j = -1; j <= 1; j++){
if(row + i >= 0 && row + i < MAP_SIZE && col + j >= 0 && col + j < MAP_SIZE){
if(map[row + i][col + j] == player){
count++;
}
}
}
}
if(count >= 5){
gameOver = 1;
}
if(player == CHESS_PLAYER1){
player = CHESS_PLAYER2;
} else {
player = CHESS_PLAYER1;
}
} else {
printf("Invalid input, please try again!\n");
}
}
int main(){
initMap();
drawMap();
player = CHESS_PLAYER1;
while(!gameOver){
input();
placeChess();
drawMap();
}
printf("Game over! Player %d wins!", player);
return 0;
}
```
这个程序实现了一个简单的穿越火线锁头游戏,使用了二维数组来表示棋盘状态,并在控制台中运行。玩家轮流输入行和列来放置棋子,并在有五个相邻棋子时获胜。游戏结束后,程序会输出获胜者的信息。
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