c语言利用循环向单链表尾插五个元素，并输出

可以回答这个问题。以下是示例代码：

#include <stdio.h>
#include <stdlib.h>

struct Node {
    int data;
    struct Node* next;
};

int main() {
    struct Node* head = NULL;
    struct Node* tail = NULL;
    int i;

    for (i = 0; i < 5; i++) {
        struct Node* newNode = (struct Node*) malloc(sizeof(struct Node));
        newNode->data = i;
        newNode->next = NULL;

        if (tail == NULL) {
            head = newNode;
            tail = newNode;
        } else {
            tail->next = newNode;
            tail = newNode;
        }
    }

    struct Node* current = head;
    while (current != NULL) {
        printf("%d ", current->data);
        current = current->next;
    }
    printf("\n");

    return 0;
}

这段代码利用循环向单链表尾插入五个元素，并输出它们的值。