A=1,3,4,5,8,10,12,13,14,16,17,20,21,25,26,28 B=1,3,4,7,11,12,15,16,19,20,22,24,28,31,32 C=2,7,10,13,15,16,19,20,22,25,26,28,29,31,33 D=1,2,3,5,8,10,14,15,17,25,26,29,33 E=3,5,8,11,12,15,19,21,24,26,30,31,33 F=3,6,8,10,12,14,15,17,20,21,29,31 G=3,4,7,12,14,16,19,21,25,28,29,31 H=4,6,10,11,12,18,19,20,22,25,26,31
时间: 2023-09-19 15:11:51 浏览: 27
根据给定的数组A、B、C、D、E、F、G、H,找出与原始数组不重复的所有6位数顺序组合。
以下是一个示例的Python代码实现:
```python
def find_unique_combinations(arr):
unique_combinations = []
for i in range(len(arr)):
for j in range(i+1, len(arr)):
for k in range(j+1, len(arr)):
for l in range(k+1, len(arr)):
for m in range(l+1, len(arr)):
for n in range(m+1, len(arr)):
combination = [arr[i], arr[j], arr[k], arr[l], arr[m], arr[n]]
unique_combinations.append(combination)
return unique_combinations
# 测试示例
A = [1,3,4,5,8,10,12,13,14,16,17,20,21,25,26,28]
B = [1,3,4,7,11,12,15,16,19,20,22,24,28,31,32]
C = [2,7,10,13,15,16,19,20,22,25,26,28,29,31,33]
D = [1,2,3,5,8,10,14,15,17,25,26,29,33]
E = [3,5,8,11,12,15,19,21,24,26,30,31,33]
F = [3,6,8,10,12,14,15,17,20,21,29,31]
G = [3,4,7,12,14,16,19,21,25,28,29,31]
H = [4,6,10,11,12,18,19,20,22,25,26,31]
arr = [A, B, C, D, E, F, G, H]
result = find_unique_combinations(arr)
print(result)
```
在这个示例中,我们定义了8个数组A、B、C、D、E、F、G、H,并将它们放入一个数组arr中。函数`find_unique_combinations`将返回与这些数组不重叠的所有6位数顺序组合。每个组合都是一个包含6个元素的列表。你可以根据你的具体需求修改代码。
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