解释C + +代码：#include <iostream> #include <map> #include <algorithm> using namespace std; int main() { int n; cin >> n; map<string, pair<int, int> > m; string name[n]; for (int i = 0; i < n; i++) { cin >> name[i]; m[name[i]].first = i + 1; } sort(name, name + n); for (int i = 0; i < n; i++) { if(m[name[i]].second == 0){ int max = n - 1; for (int j = i; j < n; j++) { if (name[i] == name[j]) max = j; } m[name[i]].second = max + 1; } } for (int i = 0; i < n; i++) { cout << m[name[i]].first << " " << m[name[i]].second << endl; } return 0; }

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竞赛题目#include <cstdio> #include <cstring> #include <ctype.h> #include <cstdlib> #include <cmath> #include <climits> #include <ctime> #include <iostream> #include <algorithm> #include <deque> #...

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using namespace std; int main(){ // 处理输入 string input_str ; cin >> input_str; map<char, int> char_count; for (auto x : input_str) { if (char_count.count(x)) { char_count[x] += 1; } else ...

#include <iostream> #include <vector> #include <string> #include <algorithm> #include <map> #include <thread> #include "List.h" #include "Node.h" using namespace std; int main(void) { auto* head = new Node<int>(10); //auto *list = new List<int>(head); List<int> list(head); //list->Display(); return 0; }

这段代码包含了 List 类和 Node 类的头文件，...因此，可以直接使用 List<int> list(head) 来创建对象。另外，注释掉的 list->Display() 可以直接通过 list.Display() 来调用，因为 Display 函数是一个公有成员函数。

#include<iostream> #include<cmath> #include<ctime> #include<cstdio> #include<fstream> #include<algorithm> #include<deque> #include<queue> #include<string> #include<map> #include<stack> #include<set> //#include<windows.h> using namespace std; int main() { int a[4][4],b[16]= { 0 } ,k=0; srand(time(0)); for (int i=0;i<4;i++) { for (int j=0;j<4;j++) { a[i][j]=rand()%10; if(a[i][j]%2==1) { b[k]=a[i][j]; ++k; } } } for (int i=0;i<k;++i) { cout<<b[i]<<" "; } return 0; }

这是一个 C++ 的程序，它生成一个 $4\times4$ 的矩阵 $a$，并将其中的奇数存入数组 $b$ 中，最后输出 $b$ 数组的内容。具体实现过程是：首先通过 srand(time(0)) 函数初始化随机数种子，接着用 rand()%10 生成 $...

#include <iostream> #include <algorithm> #include <string> #include <cstdio> #include <cmath> #include <set> #include <map> using namespace std; //const int N = 1e5 + 10; //typedef long long ll; int main() { int t; cin >> t; while (t--) { int n; set<string>a; string s; cin >> n >> s; int t = 0; for (int i = 0; i < s.size(); i++) { t = s.find(s[t]); a.insert(s.substr(i, 1)); } for (int i = 0; i < a.size(); i++) cout << a[i]; cout << endl; } return 0; }有什么问题

using namespace std; int main() { int t; cin >> t; while (t--) { int n; set<string> a; string s; cin >> n >> s; int t = 0; for (int i = 0; i < s.size(); i++) { a.insert(s.substr(i, 1)); t ...

解释这段代码：#include<iostream> #include<vector> #include<cmath> #include<algorithm> #include<map> int INF=0x3f3f3f3f; using namespace std; int main() { int n; while (cin >> n) { vector>p(n, pair<int,int>(0,0)); for (int i = 0; i < n; i++) cin >> p[i].first >> p[i].second; sort(p.begin(), p.end(), [](pair<int, int>a1, pair<int, int>a2) ->bool {return a1.first * 1.0 / a1.second > a2.first * 1.0 / a2.second; }); int count = 0; int hp = 0; for (int i = 0; i < n; i++) { hp += p[i].first * (p[i].second + count); count += p[i].second; } cout << hp << endl; } }

这段代码是一个求解背包问题的程序。它的思路是贪心算法，按照每个物品的单位价值（即单位价值 = 物品价值 / 物品重量）从大到小排序，然后逐个考虑每个物品是否放入背包中。具体实现中，首先读入物品数量n，然后...

#include <iostream> #include <fstream> #include <cstdio> #include <cstdlib> #include <cstring> #include <cmath> #include <climits> #include <string> #include <algorithm> #include <vector> #include <map> using namespace std; struct Value { char str[10000]; }; void structSort(Value *a, int n) { @你的代码 } int n; Value a[5000]; int main() { scanf("%d", &n); for (int i = 0; i<n; i++) { scanf("%s", a[i].str); } structSort(a, n); for (int i = 0; i<n; i++) { printf("%s\n", a[i].str); } return 0; }

这段代码给出了一个结构体数组 a，其中每个结构体包含一个字符串成员 str。接下来有一个函数 structSort，它需要你来实现。你需要使用任何一种排序算法对 a 数组进行排序，排序的依据是字符串的字典序（即...

#include <iostream> #include <algorithm> #include <cstdio> #include <cmath> #include <vector> #include <map> #include <vector> #include <string> #include <cstring> #define fast ios::sync_with_stdio(false),cin.tie(0) using namespace std; typedef pair<int, int> PII; typedef long long LL; const int N = 2e5+10; int T; string name[10] = {"Captain", "Priest", "Cook", "Doctor", "Engineer", "Hunter", "Gunner", "Navigator" }; map<string, int> mp; int main() { string s; cin >> s; mp[s] = 1; int n; scanf("%d", &n); for(int i = 0; i < n; i ++ ) { int j = 0; string s, t; getline(cin, s); for(int i = 0; s[i] != ':'; i ++ ) t += s[i]; mp[t] = 1; } sort(name, name + 8); int f = 0; for(int i = 0; i < 8; i ++ ) { if(mp[name[i]] == 0) cout << name[i] << endl, f ++; } if(!f) cout << "Ready" << endl; return 0; }转化为C语言代码

1. 删除头文件#include <iostream>，#include <algorithm>，#include <cstdio>，#include <cmath>，#include <vector>，#include <map>，#include <vector>，#include <string>，#include <cstring>。 2. 删除using...

#include<iostream> #include<algorithm> #include<vector> #include<deque> #include<map> #include<cstring> using namespace std; int main() { vector<int> v(10); int num; vector<int>::iterator beg = v.begin(); vector<int>::iterator end = v.end(); vector<int>::iterator mid = v.begin() + (end - beg) / 2; for (int i = 0; i < 10; i++) { v[i] = i; } cin >> num; sort(v.begin(), v.end()); while (mid != num && beg <= end) { if (num < mid) { end = mid; } else { beg = mid + 1; } mid = beg + (end - beg) / 2; } if (*mid == num) { cout << "Find" << endl; } else { cout << "Not Find" << endl; } return 0; }翻译每一行代码的意思

1. #include<iostream>：包含输入输出流库。 2. #include<algorithm>：包含算法库。 3. #include<vector>：包含向量库。 4. #include<deque>：包含双端队列库。 5. #include<map>：包含映射库。 6. #...

将下列代码转换成c语言代码：#include <iostream> #include <algorithm> #include <cstdio> #include <cmath> #include <vector> #include <map> #include <string> #include <cstring> #define fast ios::sync_with_stdio(false),cin.tie(0) using namespace std; typedef pair<int, int> PII; typedef long long LL; const int N = 1010; int T; int f1, s1, f2, s2; vector v; string x[8] = {"11111111", "10000001", "10111101", "10111101", "10111101", "10111101", "10000001", "11111111"}; int main() { int n, m; scanf("%d %d", &n, &m); string s[N]; for(int i = 0; i < n; i ++ ) { cin >> s[i]; } for(int i = 0; i <= n - 8; i ++ ) { for(int j = 0; j <= m - 8; j ++ ) { int k, cnt = 0; for(k = 0; k < 8; k ++ ) { //cout << k << " " << x[k] << " " << s[i+k].substr(j, 8) << endl; if( x[k] == s[i+k].substr(j, 8) ) cnt ++; } if(cnt == 8) v.push_back({i, j}); } } sort(v.begin(), v.end()); for(int i = 0; i < 3; i ++ ) printf("%d %d\n", v[i].first, v[i].second); return 0; }

以下是将代码转换成 C 语言代码后的结果： c #include <stdio.h> #include <string.h> #define fast {ios::sync_with_stdio(false); cin.tie(0);} typedef struct PII { int first, second; } PII; const int N...

#include <iostream> #include <cstdio> #include <vector> #include <iterator> #include <algorithm> #include <string> #include <set> #include <map> using namespace std; //cout<< //cin>> set<long long int>::iterator it; set<long long int>::iterator it1; bool pd(set<long long int > set1,set<long long int> set2) { if(set1.size()!=set2.size())return false; for(it=set1.begin(),it1=set2.begin();it!=set1.end();it++,it1++) { if(it!=it1)return false; } return true; } int main() { set<long long int> set1,set2; long long int x; while((cin>>x)) { if(x!=0)set1.insert(x); while(cin>>x&&x!=0) {set1.insert(x);} while(cin>>x&&x!=0) { set2.insert(x); } if(pd(set1,set2)==true)cout<<"YES"<<endl; else cout<<"NO"<<endl; set1.clear(); set2.clear(); } // // set_intersection()//交集 // set_union()//并集 // set_difference()//差集 // set_symmetric_difference() return 0; }这段代码哪里有问题

#include <iostream> #include <set> using namespace std; bool pd(const set<long long int>& set1, const set<long long int>& set2) { return set1 == set2; } int main() { set<long long int> set1, set2;...

把#include <iostream> #include <algorithm> #include <cstdio> #include <cmath> #include <vector> #include <map> #include <vector> #include <string> #include <cstring> #define fast ios::sync_with_stdio(false),cin.tie(0) using namespace std; typedef pair<int, int> PII; typedef long long LL; const int N = 2e5+10; int T, t; string s[3]; void init() { /* #### #### #### # # # # # # # # #/ // 第一行，中间行，和最后一行 // 构造成 #### #### #### for(int i = 0; i < 3; i ++ ) { if(i) s[0] += " "; s[0] += "###"; for(int j = 0; j < t; j ++ ) s[0] += "#"; } // 上半部分 // 构造成 # # # # s[1] += "# "; for(int i = 0; i < t; i ++ ) s[1] += " "; s[1] += "# #"; for(int i = 0; i < 2 t + 5; i ++ ) s[1] += " "; s[1] += "#"; // 下半部分 // 构造成 # # # # # s[2] += "# "; for(int i = 0; i < t; i ++ ) s[2] += " "; s[2] += "# # "; for(int i = 0; i < t; i ++ ) s[2] += " "; s[2] += "#"; for(int i = 0; i < t + 3; i ++ ) s[2] += " "; s[2] += "#"; } int main() { scanf("%d", &t); int n = t * 2 + 5; init(); for(int i = 1; i <= n; i ++ ) { if(i == 1 || i == n || i == (n + 1)/2) cout << s[0] << endl; else if(i < (n + 1) / 2) cout << s[1] << endl; else cout << s[2] << endl; } return 0; } 这段代码变成C语言

把#include <iostream>改为#include <stdio.h>，把using namespace std;删除，将cout改为printf即可： c #include <stdio.h> #include <algorithm> #include <cstdio> #include <cmath> #include <vector> #...

#include<cstdio> #include<cstdlib> #include<cstring> #include<cmath> #include<ctime> #include<iostream> #include<algorithm> #include<map> #include<stack> #include<queue> #include<vector> #include<set> #include<string> #define dd double #define ll long long dd PI = acos(-1); using namespace std; const ll MAXN = 1e5 + 5; const ll INF = 1e9 + 5; ll n; struct node { ll x, y; }s[5000]; ll dp[MAXN] = { 0 }; int main() { //ios::sync_with_stdio(false); ll n, m; cin >> n >> m; for (ll i = 1; i <= n; i++) { cin >> s[i].x >> s[i].y; } for (ll i = 1; i <= n; i++) { for (ll j = m; j >= s[i].x; j--) { dp[j] = max(dp[j], dp[j - s[i].x] + s[i].y); } } cout << dp[m] << endl; }

这是一段动态规划求解背包问题的代码，用来求解一个容量为m的背包能够装下的最大价值。具体实现过程为： 1. 定义一个结构体node，用来存储物品的重量和价值。 2. 读入物品数量n和背包容量m，然后读入每个物品的...

#include <iostream> #include <vector> #include <unordered_map> #include <queue> #include <algorithm> using namespace std; struct WordFreq { string word; int freq; bool operator<(const WordFreq& other) const { return freq == other.freq ? word > other.word : freq < other.freq; } }; vector<string> topKFrequent(vector<string>& words, int k) { unordered_map<string, int> freq; for (const auto& word : words) { freq[word]++; } priority_queue<WordFreq, vector<WordFreq>> pq; for (const auto& [word, f] : freq) { pq.push({word, f}); if (pq.size() > k) { pq.pop(); } } vector<string> result(k); for (int i = k - 1; i >= 0; i--) { result[i] = pq.top().word; pq.pop(); } return result; } int main() { int k; cin >> k; vector<string> words; string word; while (cin >> word) { if (word == "end") { break; } words.push_back(word); } auto result = topKFrequent(words, k); for (const auto& word : result) { cout << word << " "; } cout << endl; return 0; }

using namespace std; // 定义一个结构体，用于存储单词和对应的频率 struct WordFreq { string word; int freq; bool operator<(const WordFreq& other) const { // 如果频率相同，按字母顺序从小到大排序；...

#include <iostream> #include <algorithm> #include <cstring> #include <map> using namespace std; int ans; map<string, string> mp; int main() { string tmp; cin >> tmp; // 将所有长度为8的子串存储到map中 for (int i = 0; i < tmp.size() - 7; i ++) { string str = ""; for (int j = i; j < i + 8; j ++) str += tmp[j]; mp[str] = str; } int n; cin >> n; while(n --) { string s; cin >> s; sort(s.begin(), s.end()); // 枚举排列，检查是否在map中出现过 do if(mp.count(s)) ans ++; while(next_permutation(s.begin(), s.end())); } cout << ans << endl; return 0; }给这段代码加注释

#include <iostream> // 标准输入输出流 #include <algorithm> // STL算法库，包含sort()和next_permutation()等函数 #include <cstring> // 字符串操作库，包含字符串拼接等函数 #include <map> // STL容器，用于...

#include <iostream> #include <vector> #include <algorithm> #include <unordered_map> using namespace std; vector<float> findStonePairs(const vector<float> &stones, float D) { vector<vector<float>> result; unordered_map<float, int> map; for (int i = 0; i < stones.size(); i++) { float target1 = stones[i] - D; if (map.count(target1)) { return vector<float>{target1, stones[i]}; // weight // result.push_back(vector<float>{target1, stones[i]}); // weight } float target2 = stones[i] + D; if (map.count(target2)) { return vector<float>{target2, stones[i]}; // weight // result.push_back(vector<float>{target2, stones[i]}); // weight } map[stones[i]] = i; } return vector<float>{-1, -1}; } int main() { float d = 5.0; vector<float> weights_test1 = {1.3, 3.2, 6.3, 4, 6, 5}; vector<float> result_test1 = findStonePairs(weights_test1, d); cout << "test1:" << endl; for (auto x : result_test1) { cout << x << " "; cout << endl; } return 1; }为什么输出与预期不同

using namespace std; vector<vector<float>> findStonePairs(const vector<float> &stones, float D) { vector<vector<float>> result; unordered_map<float, int> map; for (int i = 0; i < stones.size()...

#include<math.h> #include<algorithm> #include<time.h> #include<stdlib.h> #include<iostream> #include<string.h> #include<map> #include #include<string> #include<queue> #include<set> #include<vector> #include<stack> #include #define re register #define iosgo() std::ios::sync_with_stdio(false),cin.tie(0),cout.tie(0); #define run(i,n) for (int i = 1; i <= n; i++) #define cin std::cin #define cout std::cout #define ll long long #define endl "\n" using namespace std; typedef pair<int, int>pll; const int N = 2e6 + 10; pll c[N]; int h[150][150]; int x[N], y[N], dp[N], ss[N]; int gcd(int a, int b) { return b ? gcd(b, a % b) : a; } signed main() { string a; cin >> a; string b; cin >> b; if (a[0] == '0' || b[0] == '0') { cout << "0\n"; return 0; } int lena = a.length(); int lenb = b.length(); for (int i = 0; i < lena; i++) { x[i] = a[i] - '0'; } for (int i = 0; i < lenb; i++) { y[i] = b[i] - '0'; } int len = lena + lenb - 1; int r = 0; while (r < lenb) { for (int i = r, j = 0; i < lena + r; i++, j++) { ss[i] += x[j] * y[r]; } r++; } for (int i = len; i > 0; i--) { if (ss[i] >= 10) { ss[i - 1] += ss[i] / 10; ss[i] %= 10; } } for (int i = 0; i < len; i++) { cout << ss[i]; } }

这段代码是一个实现两个大整数相乘的程序。代码首先读取两个大整数a和b，然后将其转换为整型数组x和y。接下来，代码计算两个整数的乘积，并将结果存储在数组ss中。最后，代码将结果输出。注意，这段代码没有考虑...

第六届蓝桥杯软件大赛A组预赛

using namespace std; int main() { int x,y,z; for(int i=1;i<=sqrt(N);i++) { for(int j=1;j<=sqrt(N);j++) { for(int k = 1;k<=sqrt(N);k++) { if(i*i + j*j + k*k==1000) { printf(...

C++求两个集合的并集

using namespace std; vector<int> unionSets(vector<int>& nums1, vector<int>& nums2) { vector<int> result; unordered_map<int, int> mp; // 将nums1中的元素添加到unordered_map中 for (int num : nums1...

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