python网络爬虫案例源码
时间: 2024-09-21 07:12:16 浏览: 38
Python网络爬虫是一种常用的技术,用于从网站上抓取数据。以下是一个简单的Python爬虫案例,使用了`requests`库来发送HTTP请求,`BeautifulSoup`库来解析HTML内容:
```python
# 导入需要的库
import requests
from bs4 import BeautifulSoup
# 定义目标URL
url = 'https://www.example.com'
# 发送GET请求
response = requests.get(url)
# 检查请求是否成功
if response.status_code == 200:
# 解析HTML内容
soup = BeautifulSoup(response.text, 'html.parser')
# 查找并提取特定的数据,例如所有链接
links = [a['href'] for a in soup.find_all('a', href=True)]
# 打印提取到的链接
for link in links:
print(link)
else:
print(f"请求失败,状态码:{response.status_code}")
相关问题
python xpath爬虫实例
以下是一个使用Python的XPath爬虫的实例:
```python
import requests
from lxml import etree
if __name__ == '__main__':
url = 'https://pic.netbian.com/4kmeinv/'
headers = {
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/84.0.4147.105 Safari/537.36'
}
page_text = requests.get(url=url, headers=headers).text
tree = etree.HTML(page_text)
li_list = tree.xpath('//div[@class="slist"]/ul/li/a')
if not os.path.exists('./piclibs'):
os.mkdir('./piclibs')
for li in li_list:
detail_url = 'https://pic.netbian.com' + li.xpath('./img/@src')[0]
detail_name = li.xpath('./img/@alt')[0 + '.jpg'
detail_name = detail_name.encode('iso-8859-1').decode('GBK')
detail_path = './piclibs/' + detail_name
detail_data = requests.get(url=detail_url, headers=headers).content
with open(detail_path, 'wb') as fp:
fp.write(detail_data)
print(detail_name, 'seccess!!')
```
这个爬虫实例通过发送网络请求获取页面源码,然后使用lxml库中的etree模块将页面源码转化为可解析的HTML树对象。之后,使用XPath语法来提取页面中的数据,例如获取图片的URL和名称。最后,将图片保存到本地文件夹。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
#### 引用[.reference_title]
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使用这些学习资料,你将理解如何使用Python编写爬虫脚本,并且可以尝试使用爬虫技术来爬取知网上的内容。祝你学习顺利!<span class="em">1</span><span class="em">2</span><span class="em">3</span>
#### 引用[.reference_title]
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