运行上面的代码出现index 1 is out of bounds for axis 0 with size 1错误
时间: 2023-09-26 12:09:23 浏览: 37
非常抱歉,这是因为np.where函数返回的是一个数组,而数组中只有一个元素时,访问索引为1的位置会超出范围。为了解决这个问题,我们可以使用[0][0]来获取数组中的唯一元素。
下面是修改后的代码,应该可以正常运行了:
```
import numpy as np
from queue import PriorityQueue
# 定义启发式函数
def heuristic(state, goal_state):
distance = 0
for i in range(3):
for j in range(3):
if state[i][j] != 0:
distance += abs(i - np.where(goal_state == state[i][j])[0][0]) + abs(j - np.where(goal_state == state[i][j])[1][0])
return distance
# 定义状态转移
def get_next_states(state):
next_states = []
i, j = np.where(state == 0)
if i > 0:
next_state = state.copy()
next_state[i][j], next_state[i-1][j] = next_state[i-1][j], next_state[i][j]
next_states.append(next_state)
if i < 2:
next_state = state.copy()
next_state[i][j], next_state[i+1][j] = next_state[i+1][j], next_state[i][j]
next_states.append(next_state)
if j > 0:
next_state = state.copy()
next_state[i][j], next_state[i][j-1] = next_state[i][j-1], next_state[i][j]
next_states.append(next_state)
if j < 2:
next_state = state.copy()
next_state[i][j], next_state[i][j+1] = next_state[i][j+1], next_state[i][j]
next_states.append(next_state)
return next_states
# 定义A*算法
def A_star(start_state, goal_state):
q = PriorityQueue()
q.put((heuristic(start_state, goal_state), start_state))
visited = set()
while not q.empty():
current_state = q.get()[1]
if (current_state == goal_state).all():
return True
visited.add(tuple(map(tuple, current_state)))
for next_state in get_next_states(current_state):
if tuple(map(tuple, next_state)) not in visited:
q.put((heuristic(next_state, goal_state), next_state))
return False
# 测试
start_array = np.array([[1, 5, 3], [2, 4, 6], [7, 0, 8]])
goal_array = np.array([[1, 2, 3], [4, 5, 6], [7, 8, 0]])
result = A_star(start_array, goal_array)
print(result)
```
希望这次可以顺利运行。