给这段代码增加一个重新开始功能 int snakedie() { if (snake.xy[0].x > 640 || snake.xy[0].y > 480 || snake.xy[0].x < 0 || snake.xy[0].y < 0) { outtextxy(200, 200, "GameOver"); MessageBox(hwnd, "GameOver!", "GameOver", MB_OK); return 1; } for (int i = 1; i < snake.num; i++) { if (snake.xy[0].x == snake.xy[i].x && snake.xy[0].y == snake.xy[i].y) { outtextxy(200, 200, "GameOver"); MessageBox(hwnd, "GameOver!", "GameOver", MB_OK); return 1; } } return 0; }

可以在游戏结束时询问用户是否要重新开始游戏，如果用户选择是，则重新初始化贪吃蛇的位置和长度等信息，否则退出游戏。

代码示例：

int snakedie() {
if (snake.xy[0].x > 640 || snake.xy[0].y > 480 || snake.xy[0].x < 0 || snake.xy[0].y < 0)
{
outtextxy(200, 200, "GameOver");
if (MessageBox(hwnd, "GameOver! Do you want to restart?", "GameOver", MB_YESNO) == IDYES)
{
// 重新开始游戏
snake.num = 3;
snake.direction = RIGHT;
snake.xy[0].x = 320;
snake.xy[0].y = 240;
snake.xy[1].x = 300;
snake.xy[1].y = 240;
snake.xy[2].x = 280;
snake.xy[2].y = 240;
return 0;
} else {
// 退出游戏
exit(0);
}
}
for (int i = 1; i < snake.num; i++)
{
if (snake.xy[0].x == snake.xy[i].x && snake.xy[0].y == snake.xy[i].y)
{
outtextxy(200, 200, "GameOver");
if (MessageBox(hwnd, "GameOver! Do you want to restart?", "GameOver", MB_YESNO) == IDYES)
{
// 重新开始游戏
snake.num = 3;
snake.direction = RIGHT;
snake.xy[0].x = 320;
snake.xy[0].y = 240;
snake.xy[1].x = 300;
snake.xy[1].y = 240;
snake.xy[2].x = 280;
snake.xy[2].y = 240;
return 0;
} else {
// 退出游戏
exit(0);
}
}
}
return 0;
}

注意，在重新开始游戏时，需要将贪吃蛇的位置、长度和方向等信息都重新初始化，以便开始新的游戏。