用Python输出ABCDE棱形

以下是用 Python 输出ABCDE棱形的代码：

n = 5
for i in range(n):
    # 打印左侧空格
    for j in range(n-i-1):
        print(" ", end="")
    # 打印左侧字符
    for j in range(i+1):
        print(chr(65+j), end="")
    # 打印右侧字符
    for j in range(i):
        print(chr(64+i-j), end="")
    # 打印右侧空格
    for j in range(n-i-1):
        print(" ", end="")
    print()  # 换行
for i in range(n-2, -1, -1):
    # 打印左侧空格
    for j in range(n-i-1):
        print(" ", end="")
    # 打印左侧字符
    for j in range(i+1):
        print(chr(65+j), end="")
    # 打印右侧字符
    for j in range(i):
        print(chr(64+i-j), end="")
    # 打印右侧空格
    for j in range(n-i-1):
        print(" ", end="")
    print()  # 换行

输出结果如下：

    A    
   ABA   
  ABCBA  
 ABCDCBA 
ABCDEDCBA
 ABCDCBA 
  ABCBA  
   ABA   
    A