Order_CNT=Order_df.groupby(['Arrive_step','Pickup_Zone','Dropoff_Zone']).count()
时间: 2023-09-06 11:12:24 浏览: 222
这段代码使用了pandas库的`groupby()`函数对`Order_df`数据表进行分组操作,根据`Arrive_step`、`Pickup_Zone`和`Dropoff_Zone`三列进行分组,并统计每组的数量。
具体来说,`groupby()`函数会将数据表按照指定列的值进行分组,然后对每个分组进行聚合操作(例如计数、求和、平均值等),最终返回一个包含聚合结果的数据表。
在这段代码中,`Order_df.groupby(['Arrive_step','Pickup_Zone','Dropoff_Zone'])`表示按照`Arrive_step`、`Pickup_Zone`和`Dropoff_Zone`三列进行分组操作,`.count()`表示对每个分组进行计数操作,即统计每个分组中有多少条数据。
最终,这段代码会返回一个名为`Order_CNT`的数据表,其中包含了按照`Arrive_step`、`Pickup_Zone`和`Dropoff_Zone`三列分组后的每个分组的数量。
相关问题
SET sql_mode = 'NO_UNSIGNED_SUBTRACTION'; select * ,exam_cnt_rank_21-exam_cnt_rank_20 as rank_delta from( select *,concat(round((exam_cnt_21-exam_cnt_20)*100/exam_cnt_20,1),'%') as growth_rate, rank()over(order by exam_cnt_20 desc) as exam_cnt_rank_20, rank()over(order by exam_cnt_21 desc) as exam_cnt_rank_21 from( select i.tag,count(if(year(submit_time)=2020 and month(submit_time)<=6,r.id,null)) as exam_cnt_20, count(if(year(submit_time)=2021 and month(submit_time)<=6,r.id,null)) as exam_cnt_21 from exam_record r left join examination_info i on r.exam_id=i.exam_id group by i.tag ) a )b where exam_cnt_20*exam_cnt_21>0 order by growth_rate desc,exam_cnt_rank_21 desc ;
这是一个MySQL查询语句,用于计算考试记录的增长率和排名差异。同时,查询中设置了sql_mode为'NO_UNSIGNED_SUBTRACTION',以避免无符号数相减时出现错误。
请注意,这是一个假设你已经创建了相关的表并插入了数据的查询语句。如果你还没有创建表或插入数据,请确保在运行此查询之前进行相应的准备工作。
以下是查询语句:
```
SET sql_mode = 'NO_UNSIGNED_SUBTRACTION';
SELECT *, exam_cnt_rank_21 - exam_cnt_rank_20 AS rank_delta
FROM (
SELECT *,
CONCAT(ROUND((exam_cnt_21 - exam_cnt_20) * 100 / exam_cnt_20, 1), '%') AS growth_rate,
RANK() OVER (ORDER BY exam_cnt_20 DESC) AS exam_cnt_rank_20,
RANK() OVER (ORDER BY exam_cnt_21 DESC) AS exam_cnt_rank_21
FROM (
SELECT i.tag,
COUNT(IF(YEAR(submit_time) = 2020 AND MONTH(submit_time) <= 6, r.id, NULL)) AS exam_cnt_20,
COUNT(IF(YEAR(submit_time) = 2021 AND MONTH(submit_time) <= 6, r.id, NULL)) AS exam_cnt_21
FROM exam_record r
LEFT JOIN examination_info i ON r.exam_id = i.exam_id
GROUP BY i.tag
) a
) b
WHERE exam_cnt_20 * exam_cnt_21 > 0
ORDER BY growth_rate DESC, exam_cnt_rank_21 DESC;
```
这个查询将返回按照考试记录的增长率和2021年上半年考试数量排名的结果集。其中,growth_rate表示增长率,exam_cnt_rank_20表示2020年上半年考试数量的排名,exam_cnt_rank_21表示2021年上半年考试数量的排名,rank_delta表示排名差异。查询结果按照增长率降序和2021年上半年考试数量排名降序排序。同时,通过`WHERE exam_cnt_20 * exam_cnt_21 > 0`条件过滤掉考试数量为零的记录。
请根据你的实际需求和数据表结构进行适当的调整和修改。
select create_date ,major_biz_name ,minor_biz_name ,minimal_biz_name ,call_type ,service_line ,finance_type ,min_cnt ,finance_user_cnt from from ( select '${zdt.addDay(-1).format("yyyy-MM")}' create_date ,major_biz_name ,minor_biz_name ,minimal_biz_name ,call_type ,service_line ,finance_type ,count(1) min_cnt from dm_pay.finance_call_in_cnt_di where substr(cast(day as string),1,6)='${zdt.addDay(-1).format("yyyyMM")}' group by major_biz_name ,minor_biz_name ,minimal_biz_name ,call_type ,service_line ,finance_type ) a left join ( select max(user_cnt) finance_user_cnt from --dm_njbi.cc_damage_kpi_v2_di dm_njbi.active_user_30days_finance_di where day =${zdt.addDay(-1).format("yyyyMMdd")} ) b on 1=1 ; sql哪里不合法
您的SQL语句中存在一处不合法的地方,即在最外层的FROM子句之后没有指定要查询的表名或子查询。您需要将要查询的表名或子查询添加到FROM子句中,例如:
```sql
SELECT
create_date,
major_biz_name,
minor_biz_name,
minimal_biz_name,
call_type,
service_line,
finance_type,
min_cnt,
finance_user_cnt
FROM (
SELECT
'${zdt.addDay(-1).format("yyyy-MM")}' AS create_date,
major_biz_name,
minor_biz_name,
minimal_biz_name,
call_type,
service_line,
finance_type,
COUNT(1) AS min_cnt
FROM dm_pay.finance_call_in_cnt_di
WHERE SUBSTR(CAST(day AS STRING), 1, 6) = '${zdt.addDay(-1).format("yyyyMM")}'
GROUP BY
major_biz_name,
minor_biz_name,
minimal_biz_name,
call_type,
service_line,
finance_type
) a
LEFT JOIN (
SELECT MAX(user_cnt) AS finance_user_cnt
FROM dm_njbi.active_user_30days_finance_di
WHERE day = ${zdt.addDay(-1).format("yyyyMMdd")}
) b ON 1=1;
```
请将您要查询的表名或子查询添加到相应位置后重新执行查询。
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