用c++写一个8个状态的状态机源码要用数组

好的，以下是基于数组的8个状态的状态机的C++源代码：

#include <iostream>

using namespace std;

enum State {
    STATE_1,
    STATE_2,
    STATE_3,
    STATE_4,
    STATE_5,
    STATE_6,
    STATE_7,
    STATE_8
};

const int NUM_STATES = 8;

// State transition table
State stateTable[NUM_STATES][NUM_STATES] = {
    { STATE_2, STATE_4, STATE_1, STATE_6, STATE_5, STATE_3, STATE_7, STATE_8 },
    { STATE_6, STATE_1, STATE_2, STATE_8, STATE_3, STATE_5, STATE_4, STATE_7 },
    { STATE_4, STATE_3, STATE_2, STATE_1, STATE_7, STATE_8, STATE_6, STATE_5 },
    { STATE_5, STATE_6, STATE_7, STATE_8, STATE_1, STATE_2, STATE_3, STATE_4 },
    { STATE_7, STATE_2, STATE_3, STATE_4, STATE_5, STATE_1, STATE_8, STATE_6 },
    { STATE_3, STATE_5, STATE_4, STATE_2, STATE_8, STATE_6, STATE_1, STATE_7 },
    { STATE_8, STATE_7, STATE_6, STATE_5, STATE_4, STATE_3, STATE_2, STATE_1 },
    { STATE_1, STATE_8, STATE_5, STATE_7, STATE_6, STATE_4, STATE_3, STATE_2 }
};

int main() {
    State currentState = STATE_1;

    while (true) {
        cout << "In state " << currentState + 1 << endl;

        // Get next state from state table
        currentState = stateTable[currentState][rand() % NUM_STATES];
    }

    return 0;
}

在这个状态机中，我们使用了一个二维数组`stateTable`来存储状态之间的转移关系。该数组的行和列索引都是从0开始，因此我们需要在输出当前状态时将状态值加1。在`while`循环中，我们使用`rand()`函数来生成一个随机数，以从当前状态的转移表中选择下一个状态。需要注意的是，这个状态机是无限循环的，因此需要手动停止程序。