char pinyin[10][5]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"}; 为什么不能写成char pinyi[12]
时间: 2024-03-10 14:41:56 浏览: 12
char pinyin[10]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"}; 这段代码定义了一个二维字符数组pinyin,其中每个元素都是一个长度为5的字符数组。每个字符数组存储了一个拼音字符串。
如果将代码改为char pinyin[12],那么定义的将是一个长度为12的一维字符数组。这样的定义方式无法存储多个拼音字符串,只能存储一个较长的字符串。
所以,根据需求,如果需要存储多个拼音字符串,应该使用二维字符数组,而不是一维字符数组。
相关问题
char pinyin[10][5]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"}; 为什么不能写成char[11]
在C语言中,字符数组的大小必须包括字符串的结束符'\0'。所以如果你要存储一个长度为10的字符串,你需要将数组的大小设置为11,其中最后一个位置用于存储结束符'\0'。如果你将数组大小设置为10,那么就没有额外的位置来存储结束符,这样会导致字符串无法正确结束,可能会引发错误或者导致意外的结果。因此,为了安全起见,你应该将字符数组的大小设置为字符串长度加1。
char pinyin[][5]= {"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};属于几行几列的二维数组,并且打印出来
这是一个1行10列的二维字符数组。可以这样打印出来:
```c++
#include <iostream>
int main() {
char pinyin[][5] = {"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};
for(int i=0; i<10; i++) {
std::cout << pinyin[0][i] << " ";
}
return 0;
}
```
输出结果为:
```
l i n g y i e r s a n
```