如果我想从某个特定的连在一起的字符开始删除，直到某个特定的连在一起的字符呢

如果你想要从字符串中删除特定的连续字符序列，可以采用以下几种常见编程语言的方法：

1. **Python**:

def delete_substring(input_string, start_substring, end_substring):
    start_index = input_string.find(start_substring)
    if start_index != -1:
        end_index = start_index + len(start_substring)
        while end_index < len(input_string) and input_string[end_index:end_index+len(end_substring)] == end_substring:
            end_index += len(end_substring)
        return input_string[:start_index] + input_string[end_index:]
    else:
        return input_string

# 示例
input_str = "Hello, World! This is a test."
new_str = delete_substring(input_str, "is", "a")

2. **JavaScript**:

function deleteSubstring(str, startSubstr, endSubstr) {
    let index = str.indexOf(startSubstr);
    if (index !== -1) {
        let endIndex = index + startSubstr.length;
        while (endIndex < str.length && str.slice(endIndex, endIndex + endSubstr.length) === endSubstr) {
            endIndex += endSubstr.length;
        }
        return str.slice(0, index) + str.slice(endIndex);
    } else {
        return str;
    }
}

// 示例
let inputStr = "Hello, World! This is a test.";
let newStr = deleteSubstring(inputStr, 'is', 'a');

3. **Java**:

public String deleteSubstring(String inputString, String startSubstring, String endSubstring) {
    int startIndex = inputString.indexOf(startSubstring);
    if (startIndex != -1) {
        int endIndex = startIndex + startSubstring.length();
        while (endIndex < inputString.length() && inputString.substring(endIndex, endIndex + endSubstring.length()).equals(endSubstring)) {
            endIndex += endSubstring.length();
        }
        return inputString.substring(0, startIndex) + inputString.substring(endIndex);
    }
    return inputString;
}

// 示例
String inputStr = "Hello, World! This is a test.";
String newStr = deleteSubstring(inputStr, "is", "a");

以上代码会找到`start_substring`的起始位置，并删除直到遇到`end_substring`为止的所有内容。