c语言代码战争类小游戏

在C语言中制作一个简单的代码战争（Tic Tac Toe）游戏，你可以创建一个二维数组来表示棋盘，然后利用循环、条件判断和用户输入来控制玩家A（X）和玩家B（O）的游戏进程。以下是一个基础版的简单实现：

#include <stdio.h>
#define SIZE 3

char board[SIZE][SIZE] = { {' ', ' ', ' ' },
                           {' ', ' ', ' ' },
                           {' ', ' ', ' ' } };

void print_board() {
    for(int i = 0; i < SIZE; i++) {
        for(int j = 0; j < SIZE; j++) {
            printf("%c ", board[i][j]);
        }
        printf("\n");
    }
}

int check_win(char player) {
    // 检查行、列和对角线是否有连续的三个同字符
    for(int i = 0; i < SIZE; i++) {
        if(board[i][0] == player && board[i][1] == player && board[i][2] == player)
            return 1;
        if(board[0][i] == player && board[1][i] == player && board[2][i] == player)
            return 1;
    }
    if(board[0][0] == player && board[1][1] == player && board[2][2] == player)
        return 1;
    if(board[0][2] == player && board[1][1] == player && board[2][0] == player)
        return 1;

    return 0;
}

int main() {
    char player = 'X'; // 初始玩家为X
    int turn = 1;

    while(1) {
        print_board();
        int row, col;
        printf("Player %c, enter row and column (0-2): ", player);
        scanf("%d%d", &row, &col);

        if(board[row][col] != ' ') {
            printf("Invalid move! Try again.\n");
            continue;
        }

        board[row][col] = player;
        if(check_win(player)) {
            printf("Player %c wins!\n", player);
            break;
        }

        if(turn % 2 == 0) {
            player = 'O'; // 如果是偶数轮，则切换到玩家B
        } else {
            player = 'X'; // 如果是奇数轮，则切换回玩家A
        }
        turn++;
    }

    return 0;
}