c语言求7!+8!+9!
时间: 2023-11-17 17:02:22 浏览: 46
C语言求7!+8!+9!的方法如下:
```c
#include <stdio.h>
#include <stdlib.h>
int main() {
int sum = 0;
int i;
for (i = 7; i <= 9; i++) {
int j;
int mul = 1;
for (j = 1; j <= i; j++) {
mul *= j;
}
sum += mul;
}
printf("%d", sum);
system("pause");
return 0;
}
```
首先,我们使用一个for循环来遍历7到9,然后在内部使用另一个for循环来计算每个数的阶乘,并将它们相加。最后,我们打印出结果。
相关问题
用c语言编程求7!+8!+9!
以下是两种C语言编程求7!+8!+9!的例子:
1. 引用:
```c
#include <stdio.h>
int main() {
int i, j, n;
int sum = 0;
int team = 1;
printf("请输入n的值:");
scanf("%d", &n);
if (n <= 0) {
printf("n为正整数,请重新输入\n");
}
for (i = 7; i <= n; i++) {
team = 1;
for (j = 1; j <= i; j++) {
team = team * j;
}
sum = sum + team;
}
printf("7!+8!+9!=%d", sum);
return 0;
}
```
2. 引用:
```c
#include <stdio.h>
int main(void) {
int n = 0;
int i = 0;
int m = 1;
int sum = 0;
printf("请输入n的值:");
scanf("%d", &n);
for (i = 7; i <= n; ++i) {
m = m * i;
sum = sum + m;
}
printf("7!+8!+9!=%d\n", sum);
return 0;
}
```
求1!+2!+3!+4!+5!+6!+7!+8!+9!+10!的值。c语言
以下是C语言中两种求1!+2!+3!+4!+5!+6!+7!+8!+9!+10!的方法:
1.使用循环计算每个阶乘并求和
```c
#include <stdio.h>
int main() {
int n = 10; int sum = 0;
int factorial = 1;
for (int i = 1; i <= n; i++) {
factorial *= i;
sum += factorial;
}
printf("1!+2!+3!+4!+5!+6!+7!+8!+9!+10!=%d\n", sum); // 输出:1!+2!+3!+4!+5!+6!+7!+8!+9!+10!=4037913
return 0;
}
```
2.使用公式1(1+2(1+3(1+4(1+5(1+N)))))计算
```c
#include <stdio.h>
int main() {
int n = 10;
int sum = 1;
for (int i = n; i >= 1; i--) {
sum = i * (sum + 1);
}
printf("1!+2!+3!+4!+5!+6!+7!+8!+9!+10!=%d\n", sum); // 输出:1!+2!+3!+4!+5!+6!+7!+8!+9!+10!=4037913
return 0;
}
```