WITH a1 as( SELECT c_id, max(score) as score FROM sc GROUP BY c_id ) SELECT sc.s_id,sc.c_id,sc.score from sc INNER JOIN a1 on sc.score = a1.score and a1.c_id = sc.c_id ORDER BY sc.score , sc.c_id GROUP BY sc.c_id,sc.score,sc.s_id HAVING MIN(sc.s_id) = sc.s_id 这个sql有什么语法错误

这个 SQL 查询有一个语法错误。错误出现在最后的 `GROUP BY` 子句之前，`ORDER BY` 子句之后。根据 SQL 标准，`GROUP BY` 子句应该在 `ORDER BY` 之前。你可以尝试将 `GROUP BY` 子句移动到 `ORDER BY` 子句之前，以修复这个错误。修正后的 SQL 查询如下所示：

WITH a1 AS (
    SELECT c_id, MAX(score) AS score
    FROM sc
    GROUP BY c_id
)
SELECT sc.s_id, sc.c_id, sc.score
FROM sc
INNER JOIN a1 ON sc.score = a1.score AND a1.c_id = sc.c_id
GROUP BY sc.c_id, sc.score, sc.s_id
HAVING MIN(sc.s_id) = sc.s_id
ORDER BY sc.score, sc.c_id;

请注意，我对 SQL 查询进行了格式化，以使其更加可读。希望对你有帮助！如果你还有其他问题，请随时提问。

相关问题

SELECT a1.id, a1.name, a1.category_id as categoryId, a2.name as categoryName, a3.id as mgId, a4.id as mid, a4.maintenance_date as maintenanceDate FROM t_goods a1 LEFT JOIN t_goods_category a2 ON a2.id = a1.category_id LEFT JOIN t_maintenance_register_goods a3 ON a3.goods_id = a1.id LEFT JOIN t_maintenance_register a4 ON a4.id = a3.register_id WHERE a1.is_delete = 0 AND a1.is_scrap = 0 这个sql语句会出现重复，重复的记录a4.maintenance_date属性会不同，只保留最早的a4.maintenance_date 帮我改一下sql

你可以使用以下 SQL 语句来查询多个表中除了时间都重复的记录，并保留时间最早的那条：

SELECT a1.id, a1.name, a1.category_id AS categoryId, a2.name AS categoryName, a3.id AS mgId, a4.id AS mid, a4.maintenance_date AS maintenanceDate
FROM t_goods a1
LEFT JOIN t_goods_category a2 ON a2.id = a1.category_id
LEFT JOIN t_maintenance_register_goods a3 ON a3.goods_id = a1.id
LEFT JOIN (
  SELECT t_maintenance_register_goods.register_id, MIN(t_maintenance_register.maintenance_date) AS maintenance_date
  FROM t_maintenance_register_goods
  LEFT JOIN t_maintenance_register ON t_maintenance_register.id = t_maintenance_register_goods.register_id
  GROUP BY t_maintenance_register_goods.register_id
) a4 ON a4.register_id = a3.register_id
WHERE a1.is_delete = 0 AND a1.is_scrap = 0

这个语句会查询多个表，并且连接列 `category_id`、`goods_id` 和 `register_id`，并保留时间最早的那条记录。你需要根据实际情况修改列名和条件。

select '2023-07-14' as sjrq, a1.s_id as s_id, a2.a1_bqnr shengao, a2.a1_bqnrmc shengao_tag_desc_ from ( select a1.s_id as s_id from biaoqian.student_class a1 ) a1 left join (select t.zj, s1.bqnr as a1_bqnr, s1.bqnrmc as a1_bqnrmc from (select t.zj from( select zj from default.lab_t10_df where yjfq = '2023-07-14' and ejfq = '1010' and sjfq = '10101007') t GROUP BY t.zj) t left join (select sjrq,cjsj,zj,bqbs,bqbslx,bqnr,bqnrmc,ylzd1,ylzd2 from default.lab_t10_df where yjfq = '2023-07-14' and ejfq = '1010' and sjfq = '10101007') s1 on t.zj= s1.zj distribute by t.zj) a2 on a1.s_id= a2.zj是什么中文意思

该 SQL 查询语句的中文意思是：从多个子查询和表连接的结果中选择了四个列，分别是：`'2023-07-14'`（作为别名 `sjrq`）、`a1.s_id`（作为别名 `s_id`）、`a2.a1_bqnr`（作为别名 `shengao`）和 `a2.a1_bqnrmc`（作为别名 `shengao_tag_desc_`）。

具体操作如下：
1. 在子查询 `a1` 中，从表 `biaoqian.student_class` 中选择了 `a1.s_id` 列（作为别名 `s_id`）。
2. 在子查询 `a2` 中，进行了一系列操作：
a. 从子查询 `t` 中选择了 `t.zj` 列。这个子查询是从表 `default.lab_t10_df` 中选择了满足条件 `yjfq = '2023-07-14' and ejfq = '1010' and sjfq = '10101007'` 的 `zj` 列，并按照 `zj` 进行分组。
b. 将子查询 `t` 的结果与表 `default.lab_t10_df` 进行左连接，连接条件是 `t.zj = s1.zj`，并选择了一些列作为结果集。这些列包括了 `sjrq, cjsj, zj, bqbs, bqbslx, bqnr, bqnrmc, ylzd1, ylzd2`。同样，这些数据也需要满足条件 `yjfq = '2023-07-14' and ejfq = '1010' and sjfq = '10101007'。
3. 最后，将子查询 `a1` 和 `a2` 进行左连接，连接条件是 `a1.s_id = a2.zj`。

请注意，我只是一个 AI 模型，无法直接执行该查询操作。您需要使用相应的数据库管理工具或编程语言来执行该查询。