python实现sm4加解密代码
时间: 2023-10-01 19:04:45 浏览: 179
要在Python中实现SM4加解密,可以使用gmssl包。首先,我们需要导入gmssl包中的sm4模块。然后,我们可以通过实例化CryptSM4对象来设置加密密钥。接下来,可以使用crypt_ecb方法对明文进行加密。最后,使用相同的密钥和crypt_ecb方法对密文进行解密。
以下是一个示例代码:
```
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相关问题
python实现sm4加解密
Python可以使用`cryptography`库来实现SM4加解密算法。以下是一个简单的示例代码:
```python
from cryptography.hazmat.primitives import padding
from cryptography.hazmat.primitives.ciphers import Cipher, algorithms, modes
def sm4_encrypt(key, plaintext):
# 对明文进行填充
padder = padding.PKCS7(128).padder()
padded_data = padder.update(plaintext) + padder.finalize()
# 生成随机IV
iv = os.urandom(16)
# 创建SM4加密器对象
cipher = Cipher(algorithms.SM4(key), modes.CBC(iv))
# 加密明文
encryptor = cipher.encryptor()
ciphertext = encryptor.update(padded_data) + encryptor.finalize()
return iv + ciphertext
def sm4_decrypt(key, ciphertext):
# 提取IV
iv = ciphertext[:16]
ciphertext = ciphertext[16:]
# 创建SM4解密器对象
cipher = Cipher(algorithms.SM4(key), modes.CBC(iv))
# 解密密文
decryptor = cipher.decryptor()
padded_data = decryptor.update(ciphertext) + decryptor.finalize()
# 去除填充
unpadder = padding.PKCS7(128).unpadder()
plaintext = unpadder.update(padded_data) + unpadder.finalize()
return plaintext
# 使用示例
key = b'\x01\x23\x45\x67\x89\xab\xcd\xef\xfe\xdc\xba\x98\x76\x54\x32\x10'
plaintext = b'Hello, World!'
ciphertext = sm4_encrypt(key, plaintext)
decrypted_plaintext = sm4_decrypt(key, ciphertext)
print("加密后的结果:", ciphertext)
print("解密后的结果:", decrypted_plaintext)
```
python实现sm4加解密算法
SM4是一种对称加密算法,也称为国密算法。下面是Python实现SM4加解密算法的示例代码:
```python
# coding=utf-8
import binascii
from Crypto.Cipher import AES
class SM4Cipher(object):
def __init__(self, key):
self.key = key
def encrypt(self, plaintext):
cipher = AES.new(self.key, AES.MODE_ECB)
ciphertext = cipher.encrypt(self.pad(plaintext))
return binascii.hexlify(ciphertext)
def decrypt(self, ciphertext):
cipher = AES.new(self.key, AES.MODE_ECB)
plaintext = cipher.decrypt(binascii.unhexlify(ciphertext))
return self.unpad(plaintext).decode('utf-8')
def pad(self, s):
bs = AES.block_size
return s + (bs - len(s) % bs) * chr(bs - len(s) % bs).encode()
def unpad(self, s):
return s[:-ord(s[len(s)-1:])]
if __name__ == '__main__':
key = b'0123456789abcdef'
plaintext = 'Hello, world!'
sm4 = SM4Cipher(key)
ciphertext = sm4.encrypt(plaintext.encode('utf-8'))
print('Ciphertext:', ciphertext)
decrypted_text = sm4.decrypt(ciphertext).encode('utf-8')
print('Decrypted text:', decrypted_text)
```
注意,这里使用了PyCryptodome库中的AES模块来实现SM4加解密算法。在进行加密和解密时,需要使用同一个密钥,否则无法正确解密。在加密时,需要先对明文进行填充操作,保证其长度是AES分组长度的整数倍。在解密时,需要先将填充的字节去掉,才能得到正确的明文。
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