32位masm下在BUFFERI 开始的区域中存放着不超过10字节的字符串， 在BUFFER2 开始的区域中存放着不超过 10字节的字符串（两个字符串均需要手动输入），将既在 BUFFERI 中又在 BUFFER2中出现的字符输出到屏幕上。

在32位MASM环境下，你可以使用以下代码结构来完成这个任务。首先，我们需要声明两个缓冲区`BUFFERI`和`BUFFER2`，以及一个辅助数组来存储重复的字符。然后，用户可以通过键盘输入字符串，程序会检查这两个缓冲区中是否同时存在相同的字符，并打印出来。

.data
BUFFERI db 10 dup(?) ; Buffer for first input
BUFFER2 db 10 dup(?) ; Buffer for second input
DUPLICATE db 26 dup(0) ; Array to store duplicate characters, assuming ASCII chars (A-Z)

.code
entry:
    ; Prompt user for the first string
    mov ah, 0Ah        ; BIOS function for buffered read
    lea dx, BUFFERI     ; Load address of buffer
    int 21h             ; Call interrupt service routine

    ; Check for duplicates in BUFFERI
    mov ecx, 0          ; Counter for checking duplicate characters
    mov si, OFFSET BUFFERI
next_char:
    lodsb               ; Load the next character from BUFFERI
    cmp al, DL          ; Compare with already stored characters
    je found_duplicate  ; If a match, jump to duplicate check
    stosb               ; Store character if not found
    inc ecx             ; Increment counter
    loop next_char      ; Continue until all characters are checked

found_duplicate:
    cmp ecx, 1           ; If more than one character matched
    jle no_duplicates   ; Go back to start if less than two

    ; Save matched character in DUPLICATE array
    mov [DUPLICATE + ecx - 2], al

no_duplicates:
    ; Prompt user for the second string
    mov ah, 0Ah
    lea dx, BUFFER2
    int 21h

    ; Check for duplicates in BUFFER2
    mov ecx, 0
    mov si, OFFSET BUFFER2
    jmp compare_chars    ; Jump to compare characters from both buffers

compare_chars:
    lodsb                ; Load character from BUFFER2
    cmp al, DL           ; Compare with same position in BUFFERI and DUPLICATE
    je print_duplicate  ; If a match, print it

    ; If character is not in DUPLICATE, continue to next
    jmp check_next_char

print_duplicate:
    mov ah, 02h         ; BIOS function for displaying character
    int 21h             ; Call interrupt service routine
    jmp check_next_char  ; Move to next character

check_next_char:
    inc si              ; Move to the next character in BUFFER2
    loop compare_chars   ; Repeat until all characters are compared

    ; Exit program
    mov ax, 0x4c00
    int 0x21

终止:
    ; Exit code or cleanup
    ret

end entry

这段代码首先提示用户输入第一个字符串，并检查其中是否有重复字符。如果有，它会保存这些字符到`DUPLICATE`数组。接着，它会提示用户输入第二个字符串，再次比较这两个字符串中的字符，并打印出共同出现的字符。

注意，这个例子仅适用于ASCII字符集。对于非ASCII字符或更复杂的需求，代码会有所不同。