c. helping the nature

c. 帮助自然

帮助自然是指我们应该尽力保护和维护自然环境，减少对自然资源的破坏和污染。这包括减少使用化学物质、节约能源、垃圾分类、植树造林等行为。通过帮助自然，我们可以保护生态系统的平衡，维护人类的健康和生存环境。

相关问题

The Sleeping Teaching Assistant A university computer science department has a teaching assistant (TA) who helps undergraduate students with their programming assignments during regular office hours. The TA’s office is rather small and has room for only one desk with a chair and computer. There are three chairs in the hallway outside the office where students can sit and wait if the TA is currently helping another student. When there are no students who need help during office hours, the TA sits at the desk and takes a nap. If a student arrives during office hours and finds the TA sleeping, the student must awaken the TA to ask for help. If a student arrives and finds the TA currently helping another student, the student sits on one of the chairs in the hallway and waits. If no chairs are available, the student will come back at a later time. Using POSIX threads, mutex locks, and/or semaphores, implement a solution that coordinates the activities of the TA and the students. Details for this assignment are provided below. Using Pthreads, begin by creating N students. Each will run as a separate thread. The TA will run as a separate thread as well. Student threads will alternate between programming for a period of time and seeking help from the TA. If the TA is available, they will obtain help. Otherwise, they will either sit in a chair in the hallway or, if no chairs are available, will resume programming and will seek help at a later time. If a student arrives and notices that the TA is sleeping, the student must notify the TA using a semaphore. When the TA finishes helping a student, the TA must check to see if there are students waiting for help in the hallway. If so, the TA must help each of these students in turn. If no students are present, the TA may return to napping. Perhaps the best option for simulating students programming—as well as the TA providing help to a student—is to have the appropriate threads sleep for a random period of time using the sleep() API:

This is a programming assignment that requires the use of POSIX threads, mutex locks, and/or semaphores to coordinate the activities of the TA and the students. Here is one possible solution:

1. Create a mutex lock and two semaphores: one for the TA and one for the students waiting in the hallway.
2. Create N student threads and one TA thread.
3. Each student thread should loop indefinitely, alternating between programming and seeking help from the TA.
4. When a student needs help, they should try to acquire the mutex lock. If the TA is sleeping, the student should signal the TA semaphore and wait on the student semaphore. If the TA is helping another student, the student should wait on the student semaphore.
5. When the TA wakes up, they should try to acquire the mutex lock. If there are students waiting in the hallway, the TA should signal the student semaphore N times to wake up the students. The TA should then help each student in turn, releasing the mutex lock after each one is helped.
6. If there are no students waiting, the TA should release the mutex lock and go back to sleep.

Here is some sample code to implement this solution:

#include <pthread.h>
#include <semaphore.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>

#define N 10 // number of students
#define CHAIRS 3 // number of chairs in hallway

pthread_t students[N], ta;
pthread_mutex_t mutex;
sem_t student_sem, ta_sem;

int waiting = 0;

void *student(void *arg) {
    int id = *(int*)arg;
    while (1) {
        // program for a random amount of time
        sleep(rand() % 10 + 1);
        printf("Student %d needs help\n", id);
        pthread_mutex_lock(&mutex);
        if (waiting < CHAIRS) {
            // there is a free chair in the hallway
            waiting++;
            printf("Student %d waiting in hallway (%d/%d)\n", id, waiting, CHAIRS);
            pthread_mutex_unlock(&mutex);
            sem_wait(&student_sem);
            waiting--;
        } else {
            // no free chairs in the hallway
            printf("Student %d will come back later\n", id);
            pthread_mutex_unlock(&mutex);
        }
        // get help from TA
        printf("Student %d getting help from TA\n", id);
        // help for a random amount of time
        sleep(rand() % 5 + 1);
    }
}

void *ta_helper(void *arg) {
    while (1) {
        // sleep until a student wakes us up
        sem_wait(&ta_sem);
        while (1) {
            pthread_mutex_lock(&mutex);
            if (waiting == 0) {
                // no students waiting, go back to sleep
                pthread_mutex_unlock(&mutex);
                break;
            }
            // help the next student in line
            waiting--;
            sem_post(&student_sem);
            printf("TA helping a student (%d/%d)\n", waiting, CHAIRS);
            pthread_mutex_unlock(&mutex);
            // help for a random amount of time
            sleep(rand() % 5 + 1);
        }
    }
}

int main() {
    // initialize mutex lock and semaphores
    pthread_mutex_init(&mutex, NULL);
    sem_init(&student_sem, 0, 0);
    sem_init(&ta_sem, 0, 0);
    // create student threads
    int student_ids[N];
    for (int i = 0; i < N; i++) {
        student_ids[i] = i;
        pthread_create(&students[i], NULL, student, &student_ids[i]);
    }
    // create TA thread
    pthread_create(&ta, NULL, ta_helper, NULL);
    // wait for threads to finish
    for (int i = 0; i < N; i++) {
        pthread_join(students[i], NULL);
    }
    pthread_join(ta, NULL);
    // clean up mutex lock and semaphores
    pthread_mutex_destroy(&mutex);
    sem_destroy(&student_sem);
    sem_destroy(&ta_sem);
    return 0;
}

Note that this is just one possible solution and there may be other ways to implement the same behavior using different synchronization primitives.

pytest.approx

pytest.approx is a utility provided by the pytest testing framework. It is used to perform approximate comparisons between floating-point values.

When writing tests for floating-point values, it is often impractical to expect exact equality due to rounding errors. pytest.approx allows you to specify a tolerance within which the values should be considered approximately equal.

Here's an example usage of pytest.approx:

def test_approximate_comparison():
    assert 0.1 + 0.2 == pytest.approx(0.3)

In this example, instead of checking for exact equality, we use pytest.approx to compare the sum of 0.1 and 0.2 with the expected value of 0.3. The assertion will pass because pytest.approx takes into account a default tolerance for floating-point comparisons.

You can also specify a custom tolerance by providing a second argument to pytest.approx, like this:

def test_custom_tolerance():
    assert 0.1 + 0.2 == pytest.approx(0.3, abs=1e-6)

In this case, we set the absolute tolerance to 1e-6, meaning that the values will be considered approximately equal if their difference is within this tolerance.

Overall, pytest.approx is a useful tool for performing approximate comparisons in tests involving floating-point numbers, helping to handle the inherent imprecision of floating-point arithmetic.