黑马程序员的PYthon语言程序设计基础(第二版)这本书的程序练习题8.1借鉴实例15.1的代码思路,采用乒乓球规则模拟比赛,分析体育竞技规律的Python详细步骤,每一步要有注释
时间: 2024-05-04 14:18:20 浏览: 16
好的,下面是详细步骤和注释:
1. 定义两个变量分别代表两个球员的初始得分,并打印输出
```python
player1_score = 0
player2_score = 0
print("比赛开始,双方得分均为0")
```
2. 定义一个变量来判断当前是哪个球员发球,初始化为1表示第一个球员发球
```python
current_serve = 1
```
3. 定义一个while循环来模拟比赛,循环条件为其中一个球员得分超过11分并且两个球员的得分差距大于等于2分
```python
while (player1_score < 11 and player2_score < 11) or abs(player1_score - player2_score) < 2:
# 循环体代码
```
4. 循环体内部先判断当前发球的球员是谁,然后根据随机数模拟是否得分,并更新得分
```python
# 判断当前是哪个球员发球
if current_serve == 1:
# 模拟球员1发球,随机数生成0或1,0表示未得分,1表示得分
if random.randint(0, 1) == 1:
player1_score += 1
print("球员1得分,当前比分为{}:{}".format(player1_score, player2_score))
else:
print("球员1未得分,当前比分为{}:{}".format(player1_score, player2_score))
else:
# 模拟球员2发球
if random.randint(0, 1) == 1:
player2_score += 1
print("球员2得分,当前比分为{}:{}".format(player1_score, player2_score))
else:
print("球员2未得分,当前比分为{}:{}".format(player1_score, player2_score))
```
5. 每次循环结束后判断是否需要交换发球权,如果当前得分为偶数,则交换发球权
```python
# 判断是否需要交换发球
if (player1_score + player2_score) % 2 == 0:
current_serve = 3 - current_serve
```
6. 循环结束后打印输出比赛结果
```python
print("比赛结束,最终比分为{}:{}".format(player1_score, player2_score))
```
完整代码如下:
```python
import random
player1_score = 0
player2_score = 0
print("比赛开始,双方得分均为0")
current_serve = 1
while (player1_score < 11 and player2_score < 11) or abs(player1_score - player2_score) < 2:
if current_serve == 1:
if random.randint(0, 1) == 1:
player1_score += 1
print("球员1得分,当前比分为{}:{}".format(player1_score, player2_score))
else:
print("球员1未得分,当前比分为{}:{}".format(player1_score, player2_score))
else:
if random.randint(0, 1) == 1:
player2_score += 1
print("球员2得分,当前比分为{}:{}".format(player1_score, player2_score))
else:
print("球员2未得分,当前比分为{}:{}".format(player1_score, player2_score))
if (player1_score + player2_score) % 2 == 0:
current_serve = 3 - current_serve
print("比赛结束,最终比分为{}:{}".format(player1_score, player2_score))
```