select title,id from label where project_id = 42 and `status` = 1 and type = 0 order by id a inner join select title,id from label a where project_id = 42 and `status` = 1 and type = 4 order by listorder b on a.title = b.title

这是一条 SQL 查询语句，目的是从一个名为 "label" 的表中获取项目ID为42、类型为0、状态为1的标签的标题和ID，同时按照ID排序；然后将结果与另一个项目ID为42、类型为4、状态为1的标签按照指定顺序排序后的标题和ID进行内连接（即只返回两个表中都有的记录），并且连接条件是这两个表中的标签标题相同。

但是，该查询语句存在语法错误，应该将 "order by id" 和 "inner join" 中间的 "a" 删除。正确的查询语句如下：

select a.title, a.id from label a inner join 
(select title, id from label where project_id = 42 and `status` = 1 and type = 4 order by listorder) b 
on a.title = b.title
where a.project_id = 42 and a.status = 1 and a.type = 0 
order by a.id