fruits = {"apple":10,"mango":12,"durian":20,"banana":5} m = 'apple' for key in fruits.keys(): #此段代码请完善 print('{}:{}'.format(m,fruits[m]))
时间: 2023-06-17 10:06:26 浏览: 61
这段代码存在问题,因为循环中并没有使用到 key,而是使用了固定的 m 变量,导致循环无意义。如果想要输出 "apple:10",可以直接使用 fruits[m]。
修正后的代码如下:
fruits = {"apple": 10, "mango": 12, "durian": 20, "banana": 5}
m = 'apple'
print('{}:{}'.format(m, fruits[m])) # 输出 "apple:10"
相关问题
fruits={"apple":10,"mango":12,"durian":20,"banana":5}输出最大键值对
以下是根据提供的引用内容给出的回答:
```python
fruits = {"apple":10, "mango":12, "durian":20, "banana":5}
m = "apple"
for key in fruits.keys():
if fruits[m] < fruits[key]:
m = key
print("最大键值的键值对为{}:{}".format(m, fruits[m]))
```
输出结果为:最大键值的键值对为durian:20
fruits = {"apple":10,"mango":12,"durian":20,"banana":5} m = 'apple' for key in fruits.keys(): print('{}:{}'.format(m,fruits[m]))完善代码,输出最大值
fruits = {"apple":10,"mango":12,"durian":20,"banana":5}
m = 'apple'
max_fruit = max(fruits, key=fruits.get)
for key in fruits.keys():
print('{}:{}'.format(m,fruits[m]))
print("Max value: {} - {}".format(max_fruit, fruits[max_fruit]))
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